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maxonik [38]
4 years ago
10

1) (Modelo lineal de costo) Juan Chávez produce juguetes didácticos, para la fabricación de estos juguetes tiene costos fijos me

nsuales de $2000 y el costo de producir cada unidad es $25. Determine una ecuación que relacione los costos. ¿Cuál es el costo de producir 200 juguetes?
Mathematics
1 answer:
grandymaker [24]4 years ago
7 0

Answer:

C = 2000 + 25 * X

$ 7000

Step-by-step explanation:

We have that the value of the total costs is equal to the fixed costs plus the variable costs.

As fixed costs we have $ 2000 and variable cost we have $ 25 for each unit, that is, the equation for total costs would be:

Let x be the number of toys, then:

C = 2000 + 25 * X

If there are 200 toys, the cost would be:

Replace x with 200:

C = 2000 + 25 * 200

C = 7000

In other words, the cost of producing 200 toys would be $ 7000.

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PLS HELP SP=3x+1, and LN=10x−6. Find SP.<br><br> A. 9<br> B. 4<br> C. 21<br> D. 7
Umnica [9.8K]

Step-by-step explanation:

2(sp)=ln

6x+2=10x-6

8=4x

x=2

therefore sp=3×2+1=6+1=7

Option D

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What is the Surface Area of this Prism?
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Answer:i Reallsjejejdhhrhrnnrr

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3 years ago
The length of a swimming pool is 4 feet longer than 2 times its width. If the perimeter of the pool is 128 feet, what is the wid
alexandr1967 [171]
P = 2(L + W)
P = 128
L = 2W + 4

128 = 2(2W + 4 + W)
128 = 2(3W + 4)
128 = 6W + 8
128 - 8 = 6W
120 = 6W
120/6 = W
20 = W <=== width is 20 ft

L = 2W + 4
L = 2(20) + 4
L = 40 + 4
L = 44 <=== length is 44 ft
5 0
4 years ago
What is the cosine of angle a?<br> a. 8/17<br> b. 15/8<br> c. 15/17<br> d. 8/15
jolli1 [7]
Check the picture below.

6 0
3 years ago
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
I am Lyosha [343]

Answer:

(a) The proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b) The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

Step-by-step explanation:

Let <em>X</em> = number of students who read above the eighth grade level.

(a)

A sample of <em>n</em> = 269 students are selected. Of these 269 students, <em>X</em> = 224 students who can read above the eighth grade level.

Compute the proportion of students who can read above the eighth grade level as follows:

\hat p=\frac{X}{n}=\frac{224}{269}=0.8327

The proportion of students who can read above the eighth grade level is 0.8327.

Compute the proportion of tenth graders reading at or below the eighth grade level as follows:

1-\hat p=1-0.8327

        =0.1673

Thus, the proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b)

the information provided is:

<em>n</em> = 709

<em>X</em> = 546

Compute the sample proportion of tenth graders reading at or below the eighth grade level as follows:

\hat q=1-\hat p

  =1-\frac{X}{n}

  =1-\frac{546}{709}

  =0.2299\\\approx 0.229

The critical value of <em>z</em> for 95% confidence interval is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the 95% confidence interval for the population proportion as follows:

CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.229\pm 1.96\times \sqrt{\frac{0.229(1-0.229)}{709}}\\=0.229\pm 0.03136\\=(0.19764, 0.26036)\\\approx (0.198, 0.260)

Thus, the 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

5 0
3 years ago
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