Answer:
36.50
To two decimal places
Step-by-step explanation:
The hypothenuse side in a right angle triangle has 58cm. While the angle touching one of its leg is 51°. How long is that leg.
From the right angled triangle, the size of the leg touching the hypothenuse is the adjacent side of the triangle, hence in trigonometry, the cosine rule is used, because it involves the adjacent and the hypotenuse.
Cos 51°=x/58
Let the size of the leg be x
Making x the subject
x=58(Cos51°)
x=36.500058
Correct to two decimal place
x=36.50
Answer:
1. 8820.26 yds^2
2. 101.265 m^2
Step-by-step explanation:
For both problems you need to use the equation π*r^2 which is the area of a circle and where r is the radius of the circle. The radius is also equal to 1/2 the diameter so using this we can figure out the are of the first circle
For the second problem we have to find the area of the circle with and without the sidewalk around it and subtract them from each other
Answer:
The surface area of Triangular base Prism = 3682 cm²
Step-by-step explanation:
Given in question as :
For a Triangular base prism ,
The base of prism (b) = 24 cm
The height of prism (l) = 29 cm
Each side length (s) = 37 cm
The height of base triangle ( h ) = 35 cm
Hence , we know that The surface area of Triangular base prism is
= (b×h) + (2×l×s) + (l×b)
= (24×35) + (2×29×37) + (29×24)
= (840) + (2146) + (696)
= 3682 cm²
Hence The surface area of Triangular base Prism is 3682 cm² Answer
