Slope is -3/5x in this equation
<span>Find the slope of the line going through the points (-9, -6) and (-18, -6).
+ The equation is y = ax+b
+ we have -6= -9a+b or b= 9a- 6
and the second: -6= -18a+b or -6= -18a+ 9a-6 or -9a=0 and a=0, b= 9*0-6= -6
The equation is: y= -6
and the slope is a=0
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The equation given above is written here below with all the terms transposed to only one side of the equation.
2x² + 3x + 8 = 0
The quadratic formula used for the determination of the roots is,
x = (-b +/- sqrt (b² - 4ac)) / 2a
In the quadratic equation above, we have the numerical coefficients.
a = 2
b = 3
c = 8
Substituting the known values,
x = (-3 +/- sqrt (3² - 4(2)(8))/ (2)(2)
x = -0.75 + 1.854i and x = -0.75 - 1.854i
By the calculated roots above, it is known that the roots are imaginary.
Answer:
The feasible region is unbounded which is the shaded portion in the graph.
Step-by-step explanation:
Given that, the number of hours Jessie works as a teacher and tutor is y and x respectively, which can't be negative.
So, 
y\ge0\;\cdots(ii)
She works at least 36 hours a week.


She works as a teacher for al least twice the number of hours she works as a tutor.

The boundary of the inequalities from equations (i), (ii), (iii), and (iv) are
and
.
The feasible region is the shaded portion which is the unbounded region as shown in the graph. Any point P(x,y) from the feasible region will satisfies all the constraints.