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Scilla [17]
2 years ago
12

What is f(g(x)) if f(x)= 4x²+3x-4 and g(x)=2x​

Mathematics
1 answer:
Yuri [45]2 years ago
5 0
I don’t know sorry I just need the points
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1oo divided into ratio 3:7
masha68 [24]
 <span>100 is not divisible by 3 when u divide 100 by 3 u get 33.333333...... not 3.33333..... 
the good explanation of your answer is that 0.999999....is equal to 1 
we can prove it by the following way: 
let x=0.9999.... 
then 10x = 9.999999..... 
subtract we will get 10x - x = 9.9999....- 0.99999...... 
which gives us 9x = 9 and therefore x =1 
i hope this will help u with your confusion.......  :)</span><span>
</span>
8 0
3 years ago
Read 2 more answers
The temperature at noon on a winter day was 8°C. At midnight, the temperature had dropped 15°C. What was the temperature at midn
klio [65]
All you have to look at is the word "dropped" and you know it's a subtraction problem. In this case, it would be 8 - 15.

8 - 15 = -7

It would be -7<span>°C at midnight. I hoped this helped! :)</span>
6 0
2 years ago
How many solutions does 2.3y+3.2-y=2.1+1.3y+1.1 have?
jeka57 [31]
1.3y +3.2 = 1.3y +3.2

we notice that both sides of the equation are identical. So substitute y with any value and the equation would still be correct.

y has infinite solutions.
6 0
3 years ago
Is my answer correct or no? <br> ---&gt; show explanation &amp; details if i am wrong!!!
neonofarm [45]

Answer:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle ⇒ 3rd answer

Step-by-step explanation:

From the graph of the circle

∵ The center of the circle F is at the origin

∴ F is (0 , 0)

∵ The circle passes through point (7 , 0)

- The length of the radius of the circle is the distance between

   the center of the circle and a point on the circle

∴ r is the distance between points (0 , 0) and (7 , 0)

∴ r=\sqrt{(7-0)^{2}+(0-0)^{2}}=\sqrt{49}=7

∴ The length of the radius of the circle is 7 units

Let us find the distance between point (7 , -7) and the origin (0 , 0)

  • If the distance is equal to the radius of the circle, then the point is on the circle
  • If the distance is greater than the radius, then the point is outside the circle
  • If the distance is less than the radius, then the point is inside the circle

∵ The distance =  \sqrt{(7-0)^{2}+(-7-0)^{2}}=\sqrt{49+49}=\sqrt{98}=7\sqrt{2}

∵ r = 7

∵ 7\sqrt{2} > 7

∴ The distance is greater than the radius of the circle

∴ Point (7 , -7) lies outside the circle

The correct answer is:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle

<em>Your answer is not correct, the correct answer is the 3rd answer</em>

3 0
3 years ago
Need help with the answer please and thank you <br> NO LINKS!<br> Have a nice day
KIM [24]

Answer: 188+22x=518 (c)

Step-by-step explanation:

7 0
2 years ago
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