Answer:
140
Step-by-step explanation:
When working HCF and LCM problems, I like to think in terms of this little diagram:
(a [ b ) c]
It shows me one of the numbers is ab, the other is bc, the HCF is b and the LCM is abc. "a" and "c" must be relatively prime for "b" to be the HCF.
__
Here, we're given ...
b = 20
ab = 320
abc = 2240
Then ...
c = abc/(ab) = 2240/320 = 7
x = bc = 20(7) . . . . . . equivalently, x = (abc·b)/(ab) = (2240·20)/320
x = 140
Answer:
A and B are correct
Step-by-step explanation:
if x:y is 1:3 then x is 1 and y is 3
1/3 of 3 is 1 so A is correct
3/4(1+3) is 3 so B is correct
But
1/4 × 3 is not 1 so C is not correct
3/4 ×1 is not 3 so D isn't correct
<span>Ending Amt = Bgng Amt * e ^-0.03t
In this equation, the "-0.03" is the decay factor or "k"
We can now solve for half-life by this equation:
</span>t = <span>(<span>ln [y(t) ÷ a]<span>)<span> ÷ -k (we can say beginning amount = 200 and ending amount = 100
</span></span></span></span>t = <span>(<span>ln [200 ÷ 100]<span>)<span> ÷ -k
</span></span></span></span>t = <span>(<span>ln [2]<span>)<span> ÷ -k
</span></span></span></span>t = 0.69314718056<span> ÷ --.03
t =</span><span><span><span> 23.1049060187
</span>
about 23 years
</span></span>
You could factor it as 2(x + 3)
It is given that John wants to find the center of a wall so he can hang a picture. So, John measures the wall and <u>determines</u> it is 65.25 inches wide. Since John has determined that the wall measures a particular amount that means that John has <u>quantified</u> the width of the wall, which in this case comes out to be 65.25 inches.
Again, this is a single number. This means that the width of the wall is a <u>discrete</u> quantity.
Thus, 65.25 inches or 65.25" is a Quantitative and Discrete type of data. Thus, out of the given options, the first option is the correct one.
