Answer:
the awnser is that Bently is 6 And Ashton is 4
Step-by-step explanation:
the reason I get this awnser is because it says that bently is 2 years older than Ashton and 3 times so you think what can be times 3 so the first awnser i got was 6 because 6 times 3 equals 18 so then I subtracted 2 from that to create the number of 6 for Bentley and 4 for Ashton
<h2>
BRAINLIEST PLEASE</h2>
Answer:
The container can hold 18 gallons
Step-by-step explanation:
Assume the container can hold x gallons
∵ The container is
full with water
∵ It can hold x gallons
→ Multiply
by x to find the number of gallons in the container
∴ The number of gallons in the container =
x
∵ 4 gallons of water pouring out
∵ It is
full
→ Multiply
by x to find the number of gallons left in it
∴ The number of gallons left in the container =
x
→ The difference between the numbers of gallons is 4 gallons
∵
x -
x = 4
→ Subtract the terms of the left side
∴
x = 4
→ Multiply both sides by 9
∴ 2x = 36
→ Divide both sides by 18
∴ x = 18
∵ x represents the full of the container
∴ The container can hold 18 gallons
Answer:
![a=-11/12](https://tex.z-dn.net/?f=a%3D-11%2F12)
Step-by-step explanation:
We are given the function:
![h(x)=ax^3 + 11 x^ 2](https://tex.z-dn.net/?f=h%28x%29%3Dax%5E3%20%2B%2011%20x%5E%202)
And we want to determine a such that h(x) has an inflection point at x = 4.
Possible inflection points are whenever h''(x) equals 0. So, we will first differentiate h(x) twice. This yields:
![h'(x)=3ax^2+22x](https://tex.z-dn.net/?f=h%27%28x%29%3D3ax%5E2%2B22x)
So:
![h^{\prime\prime} (x)=6ax+22](https://tex.z-dn.net/?f=h%5E%7B%5Cprime%5Cprime%7D%20%28x%29%3D6ax%2B22)
Inflection points occur when h''(x) = 0. So:
![0=6ax+22](https://tex.z-dn.net/?f=0%3D6ax%2B22)
Since we have an inflection at x = 4:
![0=24a+22](https://tex.z-dn.net/?f=0%3D24a%2B22)
And solving for a yields:
![a=-22/24=-11/12](https://tex.z-dn.net/?f=a%3D-22%2F24%3D-11%2F12)
Answer:
0.27
Step-by-step explanation:
Red marbles = 4
Yellow marbles = 16
Purple marbles = 5
Blue marbles = 16
Green marbles = 10
Total marbles
= 4 + 16 + 5 + 16 + 10
= 51
Red and Green marbles
= 4 + 10
= 14
P(Red or green marbles)
= 14/51
= 0.27