Mug 2 can hold the most as its volume is greater than that of mug 1
Step-by-step explanation:
To find out which mug holds more let us find the volume of each mug
As we know
Height of first mug =H1= 3 in
Diameter of first mug= D1= 5.5 in
Radius of first mug = R1=
= 2.75 in
The volume of first mug M1 is V1
The formula used will be
V=πr2h
V1 will be equal to
V1 = 51.81
Similarly
As we know
Height of second mug = H2= 4 in
Diameter of second mug = D2 = 4.5 in
Radius of second mug = R2=
= 2.25 in
The volume of second mug M2 is V2
the formula used will be
V=πr2h
V2 will be equal to
V2 = 56.52
So as V2(56.52) is greater than V1(51.81) so mug 2 can hold the most
Keywords: volume of cylinder
Learn more about volume of cylinder at:
#learnwithBrainly
Hmm, let's see. Well a triangle's dimensions add up to 180. If both sides given add up to 14. Simply subtract 180 by 14. You get, 166. If I'm wrong, feel free to correct me on that :)
Respuesta:
4 1/5 bombones
3 1/3 bombones
Explicación paso a paso:
Distribuir 21 bombones entre 5 niños;
21/5 = 4 resto 1
Por lo tanto, se le da 4 chocolates a cada niño y el 1 chocolate restante se divide en 5 partes iguales y se le da 1/5 a cada niño. Por lo tanto, cada niño recibe 4 1/5 chocolates.
Distribuir 10 bombones entre 3 niños;
10/3 = 3 resto 1
Por lo tanto, se le da 3 chocolates a cada niño y el 1 chocolate restante se divide en 3 partes iguales y se le da 1/3 a cada niño. Por lo tanto, cada niño recibe 3 1/3 chocolates.
<span>10(2y+2)−y=2(8y−8)
=
12-</span>