Answer:
<em>A=3 and B=6</em>
Step-by-step explanation:
<u>Increasing and Decreasing Intervals of Functions</u>
Given f(x) as a real function and f'(x) its first derivative.
If f'(a)>0 the function is increasing in x=a
If f'(a)<0 the function is decreasing in x=a
If f'(a)=0 the function has a critical point in x=a
As we can see, the critical points may define open intervals where the function has different behaviors.
We have

Computing the first derivative:

We find the critical points equating f'(x) to zero

Simplifying by -6

We get the critical points

They define the following intervals

Thus A=3 and B=6
Go over the x axis up 5 and over the y axis left 1
Answer:
sorry I'm too nood for that
Answer:
6x + 5y + 13 = 0.
Step-by-step explanation:
y = 5/6x + 7/6
Gradient = 5/6
Since the line is perpendicular to y = 5/6x + 7/6
then its gradient is -6/5.
Hence its equation is: point (-8,7).
y - 7 = -6/5(x -(-8))
multiplying through by 5 we get;
5y - 35 = -6(x + 8)
5y - 35 = -6x - 48
6x + 5y + 13 = 0