Answer:
4
Step-by-step explanation:
The side length would be 4, but I'm a bit confused on what the "Recall the Formula" portion is about. I'm sorry if this doesn't help
3x=78+x-2 is the answer. Good luck on your homework!
Hello,
Answer is Dsince y=k(x-2)²-5 and if k=1 ==>D.
Answer:
average atomic mass = 207.2172085 amu
Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.
For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)
The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
+ 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu
Hope this helps :)
Answer:
L = 25
Step-by-step explanation:
Let's call the Length x and width x - 15 since the width is 15 less than length
Eric needs 70 of fencing in total, the perimeter of a rectangle is calculated by adding all sides
x + x + (x - 15) + (x - 15) = 70 add like terms
4x - 30 = 70 add 30 to both sides
4x = 100 divide both sides by 4
x = 25