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wolverine [178]
3 years ago
15

Help me!! need help!!!!! 10 minutes due!

Mathematics
2 answers:
Aleks04 [339]3 years ago
6 0

Answer:

3

Step-by-step explanation:

The slope is 3 because the equation is y=mx+b. If you add in the terms m=3 and b=0. It is y=3x. M is the slope, so the slope is 3!

ddd [48]3 years ago
5 0
It would be 3.
y=mx m=slope
You might be interested in
Given cos x =12/13 And sin x = 5/13<br> what is ratio for tan x
RideAnS [48]
Its 5/12 you just divide sin by cos to get tan so divide 5/13 by 12/13 and you'll get tan
6 0
3 years ago
Read 2 more answers
11x + 2y = 68 &amp; 5x + y = 13
matrenka [14]

Answer:

i hope its correct

Step-by-step explanation:

11x + 2y=68 ------------1

5x+y=13 ------------2

y= 13-5x. ------------3

put 3 into 1

11x +2(13-5x) =68

11x +26 -10x =68

x=42

put x =42 into 2

5(42) +y =13

210+y=13

y=13-210

y=197

4 0
3 years ago
Every week a company provides fruit for its office employees. They can choose from among five kinds of fruit. What is the probab
erica [24]

Answer: D.

a p e x

this is a hard one, I tried my best. let me know in the comments if I am right. :)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Jesse made a model of a mountain range for class. to do this, he bought a cylinder of cardboard and cut it into three cones. eac
aniked [119]
By definition, the volume of the cone is given by:
 V = (1/3) (π) (r ^ 2) (h)
 Substituting values we have:
 V = (1/3) (π) ((4/2) ^ 2) (5)
 V = (20/3) (π)
 Then, the volume of the cylinder is:
 Vc = 3 * V
 Vc = 3 * (20/3) (π)
 Vc = 20π
 Answer:
 
the volume of the original cylinder jesse bought is:
 
Vc = 20π
4 0
3 years ago
HI PLEASE HELP ME WITH MY CALCULUS 1 HW? I AM REALLY STUCK. I need help with parts d,e,g.
asambeis [7]

(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when t=0 and t=3, and because the velocity function is continuous, you need only check the sign of v(t) for values on the intervals (0, 3) and (3, 6).

We have, for instance v(1)\approx-0.91 and v(4)\approx0.91>0, which means the particle is moving the positive direction for 3, or the interval (3, 6).

(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

\displaystyle\int_0^6|v(t)|\,\mathrm dt=\int_0^3-v(t)\,\mathrm dt+\int_3^6v(t)\,\mathrm dt

which follows from the definition of absolute value. In particular, if x is negative, then |x|=-x.

The total distance traveled is then 4 ft.

(g) Acceleration is the rate of change of velocity, so a(t) is the derivative of v(t):

a(t)=v'(t)=-\dfrac{\pi^2}9\cos\left(\dfrac{\pi t}3\right)

Compute the acceleration at t=4 seconds:

a(t)=\dfrac{\pi^2}{18}\dfrac{\rm ft}{\mathrm s^2}

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)

6 0
3 years ago
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