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LuckyWell [14K]
3 years ago
14

Solve each word problem using a system of equations. Use substitution or elimination.

Mathematics
1 answer:
nasty-shy [4]3 years ago
4 0

Answer:

Step-by-step explanation:

x + 3y = 24.....multiply by -1

5x + 3y = 36

------------------

-x - 3y = -24 (result of multiplying by -1)

5x + 3y = 36

------------------add

4x = 12

x = 12/4

x = 3 <=======

x + 3y = 24

3 + 3y = 24

3y = 24 - 3

3y = 21

y = 21/3

y = 7 <========

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7 times as much as the sum of 1/3 and 4/5
Jet001 [13]
First of all, you add 1/3 and 4/5, so you get:
\frac{1}{3} +  \frac{4}{5}

To add 2 fractions, they need to have the same denominator. Since 3 and 5 don't have a common factor, so you multiply 1/3 by 5, and 4/5 by 3, so you get:
\frac{1*5}{3*5} +  \frac{4*3}{5*3}
\frac{5}{15} +  \frac{12}{15}

Now, the two fractions got the same denominator, and you can add them by adding the numerators over the same denominator. (You don't add denominators in addition) so you get:
\frac{5+12}{15}
\frac{17}{15}

That's the sum of 1/3 + 4/5.

Now, they want the sum of the 2 fractions 7 times. So you multiply 17/15 by 7. And as you know, 7 = 7/1. So you get:
\frac{17}{15} *  \frac{7}{1}

In multiplication no need to have the same denominator. You multiply nominators by nominators and denominators by denominators. So you get:
\frac{17*7}{15*1}
\frac{119}{15}

Since 119 and 15 don't have a common factor, so they can't be simplified.
So, the answer is 119/15. 

Hope this Helps! :D
7 0
3 years ago
Read 2 more answers
Use the given numbers above the table in multiplying integers and to fill in the blanks inside the box.​
Jet001 [13]

Answer:

Step-by-step explanation:

1 × 5 = 5

(- 2) × (- 3) = 6

4 × (- 6) = - 24

I hope I've helped you.

8 0
3 years ago
Read 2 more answers
1. if x and y are both even whole numbers. what is a possible solution for x + y?
vivado [14]

Answer:

1. A possible solution for x +y is 9

Step-by-step explanation:

A possible solution for m-n is 0

6 0
3 years ago
True or false? The quadratic equation 10p2 - 5p = -8 has one solution.
pav-90 [236]

Answer: False

=============================================

Explanation:

I'll use x in place of p.

The original equation 10x^2-5x = -8 becomes 10x^2-5x+8 = 0 after moving everything to one side.

Compare this to ax^2+bx+c = 0

We have

  • a = 10
  • b = -5
  • c = 8

Plug those three values into the discriminant formula below

d = b^2 - 4ac

d = (-5)^2 - 4(10)(8)

d = 25 - 40*8

d = 25 - 320

d = -295

The discriminant is negative, which means we have no real solutions. If your teacher has covered complex or imaginary numbers, then you would say that the quadratic has 2 complex roots. If your teacher hasn't covered this topic yet, then you'd simply say "no real solutions".

Either way, this quadratic doesn't have exactly one solution. That only occurs when d = 0. Therefore, the original statement is false.

6 0
2 years ago
4n - 2n = 4<br> Can someone help me solve this?
Semmy [17]

Answer:

n= 2

Step-by-step explanation:

i know this is right

6 0
3 years ago
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