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posledela
3 years ago
12

Evaluate the expression for c = –1.4.

Mathematics
2 answers:
Zina [86]3 years ago
7 0

Answer:

-41.16

Step-by-step explanation:

c = -1.4

-21c²

-21(-1.4)²

-21(1.96)

-41.16

Contact [7]3 years ago
5 0

Answer:

the answer for that equation is 58.8

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The price of a shirt was reduced from $15 to $9.
Lyrx [107]

Answer:

b. 40%

Just subtract the percent 40% or .40 by 15 and you will get the awnser.

3 0
3 years ago
Seth traveled 1 mile in 57.1 seconds. About how fast does Seth travel I. Miles per hour?
enyata [817]
57.1 seconds = 57.1 seconds * \frac{1minute}{60seconds}  * \frac{1hour}{60minutes} = 0.01057 hour
1 mile / 57.1 seconds = 1 mile / 0.01057 hour = 94.57 miles/hour

4 0
4 years ago
The area of a square is 9/16 in2. What is the perimeter of the square
Alekssandra [29.7K]

Answer:

3 in²

Step-by-step explanation:

The fraction 9/16 is equal to the equation 9 ÷ 16.

9 ÷ 16 = 0.5652

Lets find the square root of 0.5652

\sqrt{0.5652} = 0.75

So the length of one side is 0.75 in²

Now we'll multiply this by 4, for the length of the 4 equal sides.

0.75 x 4 = 3.

This means the perimeter is 3 in².

5 0
3 years ago
For f(x)=4sin(x2) between x=0 and x=3, find the coordinates of all intercepts, critical points, and inflection points to two dec
telo118 [61]

Answer:

Intercepts:

x = 0, y = 0

x = 1.77, y = 0

x = 2.51, y = 0

Critical points:

x = 1.25, y = 4

x = 2.17 , y = -4

x = 2.8, y = 4

Inflection points:

x = 0.81, y = 2.44

x = 1.81, y = -0.54

x = 2.52, y = 0.27

Step-by-step explanation:

We can find the intercept by setting f(x) = 0

4sin(x^2) = 0

sin(x^2) = 0

x^2 = n\pi where n = 0, 1, 2,3, 4, 5,...

x = \sqrt(n\pi)

Since we are restricting x between 0 and 3 we can stop at n = 2

So the function f(x) intercepts at y = 0 and x:

x = 0

x = 1.77

x = 2.51

The critical points occur at the first derivative = 0

f^{'}(x) = 4cos(x^2)2x = 8xcos(x^2) = 0

xcos(x^2) = 0

x = 0 or

cos(x^2) = 0

x^2 = \frac{\pi}{2} + n\pi where n = 0, 1, 2, 3

x = \sqrt{\pi(n+1/2)}

Since we are restricting x between 0 and 3 we can stop at n =  2

So our critical points are at

x = 1.25, y = f(1.25) = 4sin(1.25^2) = 4

x = 2.17 , y = f(2.17) = 4sin(2.17^2) = -4

x = 2.8, y = f(2.8) = 4sin(2.8^2) = 4

For the inflection point, we can take the 2nd derivative and set it to 0

f^[''}(x) = 8(cos(x^2) - xsin(x^2)2x) = 8cos(x^2) - 16x^2sin(x^2) = 0

cos(x^2) = 2x^2sin(x^2)

tan(x^2) = \frac{1}{2x^2}

We can solve this numerically to get the inflection points are at

x = 0.81, y = f(0.81) = 4sin(0.81^2) = 2.44

x = 1.81, y = f(1.81) = 4sin(1.81^2) = -0.54

x = 2.52, y = f(2.52) = 4sin(2.52^2) = 0.27

3 0
3 years ago
PLEASE HELP!!
Mamont248 [21]

2 and 8 are alternate exterior angles

5 0
3 years ago
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