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nikdorinn [45]
3 years ago
15

Determine if the graph is symmetric about the x-axis, the y-axis, or the origin. r = 9 sin 7θ

Mathematics
1 answer:
boyakko [2]3 years ago
3 0

Answer:

The given function symmetric about the y-axis.

Step-by-step explanation:

The given function is

r=9\sin 7\theta                .... (1)

1. Symmetry about the x-axis: If the point (r, θ ) lies on the graph, then the point  (r,-θ ) or (-r, π - θ ) also lies on the graph.

2. Symmetry about the y-axis: If the point (r, θ ) lies on the graph, then the point (r,π - θ ) or (-r, -θ ) also lies on the graph.

3. Symmetry about the origin: If the point (r, θ ) lies on the graph, then the point (-r, θ ) or (r, π + θ ) also lies on the graph.

Put (r, -θ ) in the given function.

r=9\sin 7(-\theta)=-9\sin 7\theta=-r\neq r

Therefore it is not symmetric about x-axis.

Put (-r, -θ ) in the given function.

-r=9\sin 7(-\theta)=-9\sin 7\theta=-r

Therefore it is symmetric about y-axis.

Put (-r,θ ) in the given function.

-r=9\sin 7(\theta)=r\neq -r

Therefore it is not symmetric about the origin.

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SVEN [57.7K]

Answer:

log\boxed{7}

Step-by-step explanation:

  • log\frac{14}{3}+log\frac{11}{5}-log\frac{22}{15}

  • =log\bigg(\frac{14}{3}*\frac{11}{5}\bigg)-log\frac{22}{15}

  • =log\bigg(\frac{14*11}{3*5}\bigg)-log\frac{22}{15}

  • =log\bigg(\frac{154}{15}\bigg)-log\frac{22}{15}

  • =log\bigg(\frac{154}{15}\div\frac{22}{15}\bigg)

  • =log\bigg(\frac{154}{15}\times\frac{15}{22}\bigg)

  • =log\bigg(\frac{154}{22}\bigg)

  • =log\boxed{7}
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If X and Y are any random variables with E(X) = 5, E(Y) = 6, E(XY) = 21, V(X) = 9 and V(Y) = 10, then the relationship between X
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Answer:

We have a strong negative relationship between the variables.

Step-by-step explanation:

Given two random variables X and Y, it is possible to calculate the covariance as Cov(X, Y) = E(XY)-E(X)E(Y). We have E(X)=5, E(Y)=6 and E(XY)=21. Therefore Cov(X,Y)=21-(5)(6)=21-30=-9. On the other hand, we know that the correlation of X and Y is the number defined by Cov(X,Y)/\sqrt{Var(X)}\sqrt{Var(Y)} and because in this particular case we have V(X)=9 and V(Y)=10, we have -9/\sqrt{9}\sqrt{10} = -0.9487. Therefore, we have a strong negative relationship between the variables.

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