

- A) 2/10 + 8/100 = <u>0</u><u>.</u><u>2</u><u>8</u>
- B) 13/100 + 4/10 = <u>0</u><u>.</u><u>5</u><u>3</u>
- C) 6/10 + 39/100 = <u>0</u><u>.</u><u>9</u><u>9</u>
- D) 70/100 + 3/10 = <u>1</u>
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<em><u>#</u></em><em><u>carry </u></em><em><u>on </u></em><em><u>learning </u></em><u><</u><u>3</u>
We develop an equation for the given situation by first writing the general equation for lines,
y = mx + b
Substituting to this given the values given above,
(1990) 430 = b
(2000) 400 = m(10) + 430
The value of m from the equation in 2000 is -3. Thus, the equation of that relates the variables is,
y = -3x + 430
7-3=4
4/2=2
The answer is 2
Answer:
The component form of the vector P'P is 
Step-by-step explanation:
The component form of the vector that translates P(4, 5) to P'(-3, 7), is given as follows;
The x-component of the vector = The difference in the x-values of the point P' and the point P = -3 - 4 = -7
The y-component of the vector = The difference in the y-values of the point P' and the point P = 7 - 5 = 2
The component form of the vector P'P = 