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Shalnov [3]
3 years ago
8

which of the following is the correct value of (0.22)•(0.4)? show your reasoning. A. 8.8 B. 0.88 C. 0.088 D. 0.0088​

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
8 0

Answer:

the answer is c

Step-by-step explanation:

Luda [366]3 years ago
6 0

The answer is C because 22 × 4 = 88 and you must move the decimal point three times to the left.

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A) Two sides of a triangle are 22 inches and 17 inches.
Triss [41]
The answer would be either isosceles or scalene triangle. hope that helped
6 0
3 years ago
Read 2 more answers
What is -11 + 3(b + 5) = 7​
IRISSAK [1]

Answer:

b=1

Step-by-step explanation:

\sf -11 + 3(b + 5) = 7

<u>First, let's regroup, terms,</u>

\sf 3(b+5)-11=7

<u>Add 11 to both sides,</u>

\sf 3(b+5)=7+11

<u>Simplify, 7+11 = 18,</u>

\sf 3(b+5)=18

<u>Now, divide both sides by 3,</u>

\sf b+5=\frac{18}{3}

<u>Simplify, 18/3 = 6,</u>

\sf b+5=6

Subtract 5 from both sides,

\sf b=6-5

\sf b=1

Hope it helps! :)

7 0
2 years ago
PLZ ANSWER THIS. I really need help from smart people.
r-ruslan [8.4K]

Answer:

2x-3y<7

Step-by-step explanation:

Hope it helps (:

4 0
2 years ago
Suppose you are conducting a test of significance to try to determine whether your cat, Hope, will go to the correct object (out
ohaa [14]

In this scenario, the parameter is the sample proportion, which is of 0.7.

<h3>What is the parameter?</h3>
  • When a hypothesis is tested, the parameter is the information obtained from the sample, mean or proportion.
  • In this case, it is the <em>sample proportion</em>, which is the <u>number of desired outcomes divided by the number of total outcomes</u>.

She goes to the correct object in 70 of those 100 trials, hence:

p = \frac{70}{100} = 0.7

The parameter is the sample proportion, which is of 0.7.

You can learn more about sample proportion at brainly.com/question/25868626

4 0
2 years ago
What is the equation of a line that is parallel to the line<br> whose equation is y = x + 2?
Cloud [144]

Answer:

y=(1)x+5

Step-by-step explanation:

6 0
2 years ago
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