Answer:
The graph that have 2 lines is for Question 21 and the graph with three lines is for Question 22
Step-by-step explanation:
Answer:
The ball hit the ground at t=6 seconds
Step-by-step explanation:
we have
![f(t)=-16t^2+96t](https://tex.z-dn.net/?f=f%28t%29%3D-16t%5E2%2B96t)
where
f(t) is he height of the ball in feet
t is the time in seconds
we know that
When the ball hit the ground, the height of the ball is equal to zero
so
For f(t)=0
![-16t^2+96t=0](https://tex.z-dn.net/?f=-16t%5E2%2B96t%3D0)
solve for t
Factor the leading coefficient -16t
![-16t(t-6)=0](https://tex.z-dn.net/?f=-16t%28t-6%29%3D0)
the solutions are
t=0, t=6
Remember that
For t=0 ----> f(t)=0 is the initial height of the ball
Fort=6 sec ----> f(t)=0
therefore
The ball hit the ground at t=6 seconds
Given:
J (-2,3), K(6,5), L(0,7) and N(4,1).
Note that the midpoint of a line connecting the two points (x₁,y₁) and (x₂,y₂) is
(x,y), where
x = (x₁ + x₂)/2
y = (y₁ + y₂)/2
Calculate the midpoint for line JK.
x = (-2 + 6)/2 = 2
y = (3 + 5)/2 = 4
The midpoint of line JK is (2, 4).
Calculate the midpoint of line LN.
x = (0 + 4)/2 = 2
y = (7 + 1/2 = 4
The midpoint of line LN is (2, 4).
The midpoints for lines JK and LN are the same.
Answer:
Lines JK and LN have the same midpoint.
Answer:
The point (0,4) is a solution to the system
Step-by-step explanation:
Plug in the point (0,4) in y≥-2x+4
Then it is 4≥-2(0)+4 which equals 4≥4 which is true 4 is greater than or equal to 4