Answer:
I select b, 1,3, or 9 photos as my answer.
U + 4/5 = 2 and 1/3
Subtract 4/5 from each side of the equation:
U = (2 and 1/3) - (4/5)
Now it's just problem in plain old adding and subtracting fractions,
just like the ones you've done many times before.
First let's change (2 and 1/3) to a fraction: 2 and 1/3 = 7/3
So you have to find the value of (7/3) - (4/5) .
In order to add or subtract fractions, they need to have a common denominator.
The least common multiple of 3 and 5 is 15, so that's a good choice.
7/3 = 35/15
4/5 = 12/15
Now the problem is: (35/15) - (12/15).
That's 23/15 . . . . . the same thing as <u>1 and 8/15</u> .
That's the value of ' U '. What an ugly number !
the answer is
<span>[√8k ]² =k²,
so 8k=k² which implies k² - 8k= 0, and (k
– 8)k= 0, so k = 8 or k =0</span>
The data are bunched towards the higher values above the mean, but spread out to values below the mean. Therefore the median provides a better description of the center.
"<span>The volume of a cylinder with height h and radius r is given by the formula below. V = Πr 2 h Complete the equation below by writing an equation equivalent to height, h, of a cylinder.
Please, instead of "</span>V = Πr 2 h," type V = pi*r^2*h: "pi times radius squared times h"
V
This can be solved for the height of a cyl.: h = ---------
pi*r^2
Use " ^ " to denote exponentiation, please.
