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wlad13 [49]
3 years ago
14

On a map with a scale of 0.25 inch = 30 miles the distance between two cities is 8.3 inches

Mathematics
1 answer:
Irina-Kira [14]3 years ago
7 0

Answer:

Step-by-step explanation:

8.3÷0.25

Multiply that by 30 and you get 996

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Multiply:<br> x (x^2+2x+4) and -2 (x^2+2x+4)<br><br> Combine like terms.<br><br> Final Answer:
natulia [17]

Answer:

x^3-8

Step-by-step explanation:

x^3+2x^2+4x + -2x^2-4x-8

+2x^2 and -2x^2 cancel out

+4x and -4x cancel out

5 0
3 years ago
At Ralph's fruitstand three apples cost of $.90 you want to buy seven apples how much will they cost
Nata [24]
1 apple is $.30. $.30 times 7 = $2.10. 
3 0
3 years ago
Given a cube with a volume of 36 cm3, what is the volume of a square pyramid that can fit perfectly inside the cube?
LUCKY_DIMON [66]
Hope you know that formula for volume of a cube is area of base time height 
and volume of a square pyramid is area of base time height divide 3 
- so in this your exercise case we know that area of cube is 36 cm^3 what is area of base time height 
- so this mean that the volume of a square pyramide what can fit perfectly inside the cube will be equal 36/3 = 12 cm^3
5 0
3 years ago
Read 2 more answers
Given that f(x) = ax – 5 and f(4) = 15, determine the value of a.
agasfer [191]

Given that f(x) = ax – 5 and f(4) = 15, then the value of a is 5

The given function is:

f(x)  =  ax  -  5

If f(4)  =  15, then x = 4

Substitute x = 4 into f(x) = ax - 5

f(4)  =  a(4)  -  5

15   =  4a   -  5

Solve for a by adding 5 to both sides

15  +  5  =  4a  -  5  +  5

20    =  4a

Divide both sides by 4

4a/4   =  20/4

a    =  5

Given that f(x) = ax – 5 and f(4) = 15, then the value of a is 5

Learn more on linear functions here: brainly.com/question/15602982

8 0
2 years ago
Assume a researcher recruits 150 African American and Caucasian individuals taking warfarin to determine if there is a differenc
Anettt [7]

Answer:

Z=11.0

Step-by-step explanation:

Let Caucasian individuals be the population 1 and African American be the population 2. So, we are given that

n=150

n1=75

mean1=xbar1=6.1.

standard deviation1=S.D1=σ1=1.1.

Variance1=V(x1)=σ1²=1.1²=1.21.

n2=75.

mean2=xbar2=4.3.

standard deviation2=S.D2=σ2=0.9.

Variance2=V(x2)=σ2²=0.9²=0.81.

The z-statistic is

Z=\frac{xbar1-xbar2}{\sqrt{\frac{V(x1)}{n1}+ \frac{V(x2)}{n2} } }

Z=\frac{6.1-4.3}{\sqrt{\frac{1.21}{75}+ \frac{0.81}{75} } }

Z=\frac{1.8}{\sqrt{0.0161+ 0.0108 } }

Z=\frac{1.8}{\sqrt{0.0269 } }

Z=\frac{1.8}{0.164 } }

Z=10.97

Z=11.0

So, the z value obtained while calculating the test statistic is approximately 11.0.

4 0
3 years ago
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