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Afina-wow [57]
3 years ago
15

Find the Quadratice function

alt="y=a(x-h)x^{2}" align="absmiddle" class="latex-formula"> with given vertex (5,8) and given point (1,3)
Mathematics
1 answer:
Pani-rosa [81]3 years ago
4 0

Given:

Consider the quadratic function is

y=a(x-h)^2+k

With given vertex (5,8) and given point (1,3).

To find:

The equation of quadratic function.

Solution:

The quadratic function is

y=a(x-h)^2+k               ...(i)

Where, (h,k) is the vertex and a is a constant.

Vertex is (5,8). So,

(5,8)=(h,k)

h=5,k=8

Putting h=5,k=8 in (i), we get

y=a(x-5)^2+8           ...(ii)

The given point is (1,3). Putting x=1 and y=3 in  (ii), we get

3=a(1-5)^2+8

3-8=a(-4)^2

-5=16a

-\dfrac{5}{16}=a

Putting a=-\dfrac{5}{16} in (ii), we get

y=-\dfrac{5}{16}(x-5)^2+8

Therefore, the required quadratic function is y=-\dfrac{5}{16}(x-5)^2+8.

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