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3 years ago

7

A 39 inch piece of steel cut into 3 pieces so that the second piece is twice as long as the first piece and the third piece is t

hree inches more than six times the first one. What are the lengths of the three pieces

1 answer:

dalvyx [7]3 years ago

4 0

The length of the first piece is 4 the second piece is 8 and the third piece is 27. Your Welcome

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Solve for x. Assume that segments that appear to be tangent are tangent. Round your final answer to the nearest tenth, if necess

Butoxors [25]

Answer:

x= 16.6

Step-by-step explanation:

The circle is unnecessary. You can just use Pythag Theorem

so

9^2+14^2= c^2

81 + 196 = 277

square root 277

16.64

round to the nearest tenth...

16.6

6 0

3 years ago

Is this answer right?? If not what’s the real answer? I’m trying to practice for my STAAR.

Ierofanga [76]

35

Area of rectangle

21m^2

Area of one triangle

divide length of 7 by 2 (3.5)

gives you length b (unknown side that is not hypotenuse)

then multiply by width of triangle (4)

3.5 * 4 = 14

and in this situation there is no need to divide by two, because you essentially have one full square from both the triangles. this only works when both triangles are the same.

add the area of the rectangle

14+21= 35

35m^2

8 0

3 years ago

A parking lot has two entrances. Cars arrive at entrance I according to a Poisson distribution at an average of 3 per hour and a

alina1380 [7]

Answer:

Step-by-step explanation:

Given that a parking lot has two entrances. Cars arrive at entrance I according to a Poisson distribution at an average of 3 per hour and at entrance II according to a Poisson distribution at an average of 2 per hour.

Assuming the number of cars arriving at the two parking lots are independent we have total number of cars arriving X is Poisson with parameter 3+2 = 5

X is Poisson with mean = 5

the probability that a total of 3 cars will arrive at the parking lot in a given hour

= P(X=3) = 0.1404

b) the probability that less than 3 cars will arrive at the parking lot in a given hour

= P(X<3)

= P(0)+P(1)+P(2)

= 0.1247

7 0

4 years ago

Read 2 more answers

Help for good luck<br> and a lot of money

Alex777 [14]

1= 12.2
8=97.6
and for the last one the answer is 10 :))

5 0

2 years ago

Read 2 more answers

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

5 0

3 years ago