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kramer
3 years ago
5

I need to find the volume of the cube using v=l*w*h

Mathematics
2 answers:
scoray [572]3 years ago
7 0
Since it is a cube, each side is the same length. Therefore, it would be:
l = (x+5)*(x+5)*(x+5)
Which is the same as
x^3 [Cubed] + 125 = L
dimulka [17.4K]3 years ago
6 0
3(x+5) each side is x+5 so times that by 3. Distribute the 3 to both the x and the 5 to get 3x+15.
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Differentiate x^2 e^x logx
zimovet [89]

Product rule:

\dfrac{\mathrm d}{\mathrm dx}(x^2e^x\log x)

=\dfrac{\mathrm d(x^2)}{\mathrm dx}e^x\log x+x^2\dfrac{\mathrm d(e^x)}{\mathrm dx}\log x+x^2e^x\dfrac{\mathrm d(\log x)}{\mathrm dx}

Power rule:

\dfrac{\mathrm d(x^2)}{\mathrm dx}=2x

The exponential function is its own derivative:

\dfrac{\mathrm d(e^x)}{\mathrm dx}=e^x

Assuming the base of \log x is e, its derivative is

\dfrac{\mathrm d(\log x)}{\mathrm dx}=\dfrac1x

But if you mean a logarithm of arbitrary base b, we have

y=\log_bx\implies x=b^y=e^{y\ln b}\implies1=e^{y\ln b}\ln b\dfrac{\mathrm dy}{\mathrm dx}

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{e^{-y\ln b}}{\ln b}=\dfrac1{b^y\ln b}

\implies\dfrac{\mathrm d(\log_bx)}{\mathrm dx}=\dfrac1{x\ln b}

So we end up with

2xe^x\log x+x^2e^x\log x+\dfrac{x^2e^x}x

=xe^x(2\log x+x\log x+1)

8 0
3 years ago
What is a logarithmic function?
max2010maxim [7]

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Paul bought a soft drink and a sandwich for $9.90. What equation may be used to find the price of each item if the sandwich cost
UNO [17]

Answer:

D

Step-by-step explanation:

The other ones don't make sense. The answer is 3.5x+x=9.90

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sergeinik [125]

Answer:

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