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Nat2105 [25]
4 years ago
12

When a substance changes from one phase to another, which of the following events occurs?

Physics
2 answers:
mojhsa [17]4 years ago
5 0

Heat is transferred when a substance changes phases. Substances can be made to change phases by fluctuating the temperature, the pressure, or both. I hope I could help!

torisob [31]4 years ago
3 0

Answer

Correct Answer is

Heat is added or lost

Explanation

we know that there are four well know phases these are as follows

1. solid

2.liquid

3.gas

4. plasma

when a material changes from one phase to another phase this phenomena is known as phase change

for example conversion of water from liquid form to vapor form is a phase change.

In all phase changes like change of solid phase to liquid phase, change of liquid phase to vapor phase or vapor to liquid phase heat  is always involved to change the bonding between the molecules of substance. When liquid changes to solid form that time Heat leaves the liquid as it freezes.During these phase changes average kinetic energy does not change nor temperature changes

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A baseball rolls along a flat parking lot in a straight line at a constant speed of 3.8 m/s. How
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This is a uniform rectilinear motion (MRU) exercise.

To start solving this exercise, we obtain the following data:

<h3><u>DATA:</u></h3>
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To calculate the distance, multiply the speed by the time.

We apply the following formula: d = v * t

We clear our data in the formula:

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If an object absorbs light energy, its thermal energy __________.
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A motorboat is tied to a dock with its motor running. The spinning propeller makes a surface wave that moves at a speed of 400 c
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Light of wavelength 630 nm is incident on a long, narrow slit. Determine the angular deflection of the first diffraction minimum
asambeis [7]

Answer:

a) 1.8°

b) 0.18°

c) 0.018°

Explanation:

Wavelength (λ) = 630nm = 630 *10^-9m

The equation that describes the angular deflection of a dark band is

Wsin(βm) = mλ

w = width of the single slit

λ = wavelength of the light

βm = angular deflection of the mth dark band.

a) In order to get the angular deflection of the first dark band for a slit with 0.02mm width, substitute w = 0.02mm = 0.02*10^-3 , m = 1 , λ= 630*10^-9

0.02*10^-3 sin(β1) = 1 * 630*10^-9

Sin(β1) = 630 * 10^-9 / 0.02*10^-3

Sin(β1) = 0.0315

β1 = Sin^-1(0.0315)

= 1.8°

b) substitute w = 0.2mm = 0.2*10^-3 , m = 1 , λ= 630*10^-9

0.2*10^-3 sin(β1) = 1 * 630*10^-9

Sin(β1) = 630 * 10^-9 / 0.2*10^-3

Sin(β1) = 0.00315

β1 = Sin^-1(0.00315)

= 0.18°

c) substitute w = 2mm = 2*10^-3 , m = 1 , λ= 630*10^-9

2*10^-3 sin(β1) = 1 * 630*10^-9

Sin(β1) = 630 * 10^-9 / 2*10^-3

Sin(β1) = 3.15*10^-4

β1 = Sin^-1(3.15*10^-4)

= 0.018°

6 0
3 years ago
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