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algol13
3 years ago
5

The human eye can readily detect wavelengths from about 400 nm to 700 nm. Part A If white light illuminates a diffraction gratin

g having 910 lines/mm , over what range of angles does the visible m
Physics
1 answer:
Serga [27]3 years ago
6 0

Answer:

The correct answer is "21.344^{\circ}" and "39.56^{\circ}".

Explanation:

According to the question,

Slit width,

d=\frac{1}{910 \ lines/mm}

  =\frac{1}{910\times 10^3}

  =1.099\times 10^{-6} \ m

The condition far first order maxima will be:

⇒ d Sin \theta = 1 \lambda

Now,

⇒ \Theta_{min} = Sin^{-1} (\frac{\lambda}{d} )

             =Sin^{-1} (\frac{400\times 10^{-9}}{1.099\times 10^{-6}} )

             =21.344^{\circ}

⇒ \Theta_{max} = Sin^{-1} (\frac{\lambda}{d} )

             =Sin^{-1} (\frac{700\times 10^{-9}}{1.099\times 10^{-6}} )

             =39.56^{\circ}

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3 years ago
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4 years ago
Ask Your Teacher The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 2.0 rev/s
adell [148]

Answer:

\theta = 20\ rev

Explanation:

Case 1

Given,

initial angular speed = 0 rev/s

final angular speed = 2 rev/s

time, t = 7 s

angular acceleration of the washer

\alpha = \dfrac{\omega_f-\omega_i}{t}

\alpha = \dfrac{2-0}{7}

\alpha = 0.286\ rev/s^2

using equation of rotational motion

\omega_f^2 = \omega_i^2 + 2 \alpha \theta_1

2^2 = 0^2 + 2\times 0.286 \times \theta_1

\theta_1 = 7 rev

Case 2

Given,

initial angular speed = 2 rev/s

final angular speed = 0 rev/s

time, t = 12 s

angular acceleration of the washer

\alpha = \dfrac{\omega_f-\omega_i}{t}

\alpha = \dfrac{0-2}{13}

\alpha = -0.154\ rev/s^2

using equation of rotational motion

\omega_f^2 = \omega_i^2 + 2 \alpha \theta_2

0^2 = 2^2 + 2\times (-0.154) \times \theta_2

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\theta = \theta_1 + \theta_2

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6 0
3 years ago
Please help! Will give brainliest. 10 points. Show work!
Natasha_Volkova [10]

Answer:

421.83 m.

Explanation:

The following data were obtained from the question:

Height (h) = 396.9 m

Initial velocity (u) = 46.87 m/s

Horizontal distance (s) =...?

First, we shall determine the time taken for the ball to get to the ground.

This can be calculated by doing the following:

t = √(2h/g)

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) = 396.9 m

Time (t) =.?

t = √(2h/g)

t = √(2 x 396.9 / 9.8)

t = √81

t = 9 secs.

Therefore, it took 9 secs fir the ball to get to the ground.

Finally, we shall determine the horizontal distance travelled by the ball as illustrated below:

Time (t) = 9 secs.

Initial velocity (u) = 46.87 m/s

Horizontal distance (s) =...?

s = ut

s = 46.87 x 9

s = 421.83 m

Therefore, the horizontal distance travelled by the ball is 421.83 m

5 0
3 years ago
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