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Alenkinab [10]
3 years ago
14

At what condition does a body becomes weightless at the equator?

Physics
1 answer:
ArbitrLikvidat [17]3 years ago
4 0

Answer:

The decrease is due to the bulge at the equator (putting more distance between the rest of the planet and the surface

Explanation:

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A grocery shopper tosses a(n) 9.4 kg bag of rice into a stationary 19.9 kg grocery cart. The bag hits the cart with a horizontal
IRINA_888 [86]

The final speed of the cart and the bag is 2.2 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the bag and the cart must be conserved before and after the collision.

Mathematically:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 = 9.4 kg is the mass of the bag of rice

u_1 = 7.0 m/s is the initial velocity of the bag

m_2 = 19.9 kg is the mass of the cart

u_2 =0 m/s is the initial velocity of the cart (at rest)

v is the final combined velocity of the bag and the cart

Re-arranging the equation and solving for v, we find:  

v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{(9.4)(7.0)+0}{9.4+19.9}=2.2 m/s

Learn more about momentum here:

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5 0
3 years ago
what is the magnitude of g at a height above earth surface where free fall acceleration equal 6.5m/s2
ZanzabumX [31]
The magnitude of gravity is expressed in terms of its acceleration. So the magnitude of ' g ' at that altitude is exactly 6.5 m/s^2.
8 0
3 years ago
A spring, having an unstretched length of 2ft, has one end attached to the 10lb ball. determine the angle ? of the spring if the
Ganezh [65]
The angle theta of the spring is 31 degrees. To solve for this, show the equation which is equal to the 10lb ball. With this, the unknown will be the angle. Then transpose/transfer the terms in order to isolate the variable for the angle. First solve for s, then solve for angle theta. You will come up with s = .5849 ft and angle theta = 31.2629 or 31 degrees. Hope this helps.
5 0
4 years ago
You should be extra careful during the hours of sunrise, sunset, and nighttime because
skelet666 [1.2K]

Poor visibility, difficulties in colour perception, lessened colour contrast vision due to darker shadows and reduced peripheral vision, these are the reasons why one has to be extra careful while driving during hours of sunrise, sunset and night time.  

<h3><u> Explanation: </u></h3>

Sunrise, sunset and night time are parts of the day with minimal or absolutely no presence of sunlight. To safely navigate roads, we require enough light in order to detect presence of other vehicles, signs and pedestrians. Less sunlight during sunrise and sunset light the sky but makes the roads and vehicles have a darker, less bright view. The contrast between colours is the least, making it difficult to identify objects and see clearly.  

A rising or a setting sun can also lead to glares on the driver’s view and thus obstruct it. Since a change in ambient light is observed, our eyes need to adjust with this change and this isn’t spontaneous. Night time driving has headlight glares from approaching vehicles and reduced surrounding visibility. The eyes switching for vision adaptability from dark to bright light if vehicles approach and pass by is not a quick action. Hence the driver’s vision is compromised in every such case and this may lead to accidents.  

7 0
4 years ago
What s the rate of acceleration of gravity?​
Ivenika [448]
The numerical value for the acceleration of gravity is most accurately known as 9.8 m/s/s.
4 0
3 years ago
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