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Masja [62]
3 years ago
15

1. Which of the following is not an example of friction?

Physics
1 answer:
mario62 [17]3 years ago
8 0

ueirudjrufu rhfyrhfy. fur dhrbrhfbf

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Which option gives an object's volume in Sl units?
Phoenix [80]

Answer:

B.

Explanation:

K is the SI unit for Kelvin which measures temperature.

kg is NOT an SI unit, g is the SI unit for mass.

L is NOT an SI unit, m^3 is the SI unit for volume.

Therefore the answer is B.

3 0
3 years ago
When driving at night switch to low-beams whenever you come within ___ ft of an oncoming vehicle.
Ainat [17]
B. 500ft.  If you are driving at night with high beams on you must dim them within 500 feet of an oncoming vehicle.
3 0
3 years ago
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20 POINTS 20 POINTS On a bright sunny day you decide to take a walk. You begin at your home and walk 1000 meters to an ice cream
Kay [80]

Answer:

A) Total Distance = 2000 m and Total displacement = 0 m

B) Average Speed = 44.44 m/min and Average Velocity = 0 m/min

C) Average Speed = 0.7407 m/s and Average velocity = 0 m/s

Explanation:

A) Distance to reach ice cream shop from home = 1000 meters

Therefore distance to get back home would also be 1000 meters.

Total distance traveled = 1000 + 1000 = 2000 metres

Since journey started at home and ended at home, then total displacement = 0 metres.

B) Average speed = Total distance/total time.

Total time = 10 + 15 + 20 = 45 minutes

Since total distance = 2000 m

Then;

Average speed = 2000/45

Average speed = 44.44 m/min

Average velocity = Total displacement/total time

Average velocity = 0/45 = 0 m/min

C) We now want answers in B to be in m/s.

Total time = 45 minutes.

From conversion, 60 seconds make 1 minute. Thus, 45 minutes = 45 × 60 = 2700 seconds

Thus;

Average Speed = 2000/2700

Average Speed = 0.7407 m/s

Average displacement = 0/2700 = 0 m/s

4 0
3 years ago
The energy released from condensation in thunderstorms can be very large. Calculate the energy (in J) released into the atmosphe
makkiz [27]

Answer:

7.19 * 10^14J

Explanation:

Given that

Density of water Pwater= 1000kg/m3

R=2.1km = 2.1*10^3m

H= 2.3cm. = 2.3*10^-2m

Lv water= 2256 * 10^3J/kg

First, mass of water need to be calculated, using an imaginary cylinder

Density= Mass /Volume

Mass= Density* Volume

Volume of a cylinder= πR2h

Therefore mass= PπR2H

= 1000 * π * (2.1 *10^3)^2 * (2.3 * 10^-2)

= 3.18 *10^8

Heat Released Qv = mLV

= 3.18*10^8 * 2236*10^3

= 7.19 * 10^14J

7 0
3 years ago
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What happens when light strikes a translucent object?
sammy [17]

Answer:

D)   Some of the light passes through, and some of the light is absorbed or scattered by the object.

Explanation:

When light strikes translucent materials, only some of the light passes through them. The light does not pass directly through the materials. ... When light strikes an opaque object none of it passes through. Most of the light is either reflected by the object or absorbed and converted to heat.

(I googled it) ☺

3 0
3 years ago
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