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natka813 [3]
3 years ago
15

Multiply.use estimation to check your answer. 4 × 1.2

Mathematics
1 answer:
myrzilka [38]3 years ago
6 0

Answer:

4.8, 135, 0.2822, 0.024

Step-by-step explanation:

4*1.2=4.8

7.5*18=135

0.34*0.83=0.2822

0.04*0.6=0.024

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Halp me halp me <br> halp me halp me
atroni [7]

Answer:

8.72

Step-by-step explanation:

sqrt of 76 is 8.717 which rounded to the nearest hundereth is 8.72

8 0
2 years ago
Point B is the center of a circle, and AC is a diameter of the circle. Point D is a point on the circle different from A and C.
seropon [69]

BA and BD are radii of the circle, so triangle ABD is isosceles. Then angles BDA and BAD are congruent, and the remaining (central) angle ABD has measure

m\angle ABD=(180-2\cdot20)^\circ=140^\circ

Angles ABD and CBD are supplementary, so

m\angle CBD=(180-140)^\circ=40^\circ

and the answer is E.

8 0
4 years ago
Can someone help me plz??
Brut [27]

Answer:

96π

Step-by-step explanation:

v =  \frac{1}{3}  {r}^{2} h\pi

V=96π

5 0
3 years ago
7 rectangles in every 140 cm.how many rectangles will be presented in 220 cm
Monica [59]
140/7=20
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the answer is 11
5 0
4 years ago
* Let S = Span {(2,-1, 1), (3, 1, 1), (1, 2, 0)}. (i) Calculate the dimension of S.
Sholpan [36]

The span of 3 vectors can have dimension at most 3, so 9 is certainly not correct.

Check whether the 3 vectors are linearly independent. If they are not, then there is some choice of scalars c_1,c_2,c_3 (not all zero) such that

c_1 (2,-1,1) + c_2 (3,1,1) + c_3 (1,2,0) = (0,0,0)

which leads to the system of linear equations,

\begin{cases} 2c_1 + 3c_2 + c_3 = 0 \\ -c_1 + c_2 + 2c_3 = 0 \\ c_1 + c_2 = 0 \end{cases}

From the third equation, we have c_1=-c_2, and substituting this into the second equation gives

-c_1 + c_2 + 2c_3 = 2c_2 + 2c_3 = 0 \implies c_2 + c_3 = 0 \implies c_2 = -c_3

and in turn, c_1=c_3. Substituting these into the first equation gives

2c_1 + 3c_2 + c_3 = 2c_3 - 3c_3 + c_3 = 0 \implies 0=0

which tells us that any value of c_3 will work. If c_3 = t, then c_1=t and c_2 = -t. Therefore the 3 vectors are not linearly independent, so their span cannot have dimension 3.

Repeating the calculations above while taking only 2 of the given vectors at a time, we see that they are pairwise linearly independent, so the span of each pair has dimension 2. This means the span of all 3 vectors taken at once must be 2.

3 0
2 years ago
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