John sold 18 general admission tickets and 11 VIP tickets.
Step-by-step explanation:
Given,
Cost of each general admission = $50
Cost of each VIP ticket = $55
Total tickets sold = 29
Total revenue generated = $1505
Let,
x represent the number of general admission tickets sold
y represent the number of VIP tickets.
x+y=29 Eqn 1
50x+55y=1505 Eqn 2
Multiplying Eqn 1 by 50
Subtracting Eqn 3 from Eqn 2
Dividing both sides by 5
Putting y=11 in Eqn 1
John sold 18 general admission tickets and 11 VIP tickets.
Keywords: linear equation, elimination method
Learn more about elimination method at:
#LearnwithBrainly
There is only one solution in the given equation -y2 − [-5y − y(-7y − 9)] − [-y (15y + 4)] = 0. In solving this problem, apply first PEMDAS (parenthesis, exponents,multiplication, division, addition, subtraction). Then equation will transform into -y2+5y-7y2-9y+15y2+4y=0. Combine terms with same power and achieve 7y2=0. Divide both sides with 7 and perform square root of zero. Since the root is zero, we have one solution of the given equation which is y=0.
If all were dimes, the value would be $3.30. Brendan has $2.85 more than that. Each quarter that replaces a dime increases the value by $0.15, so Brendan must have $2.85/$0.15 = 19 quarters.
Brendan has 14 dimes and 19 quarters.
Answer:
120 units²
Step-by-step explanation:
Perimeter = PS + SQ + PQ
50 = SQ + SQ + (SQ -1)
51 = 3SQ
17 = SQ
17 -1 = 16 = PQ
The midpoint of the base is one leg of the right triangle whose other leg is the height of this isosceles triangle. That height is ...
h = √(17² -(16/2)²) = √225 = 15
Then the area is ...
A = (1/2)bh = (1/2)(16)(15) = 120 . . . . . square units
