The frequency in a study like this means the number of people which chose that option. Since the patients must chose one of them, then the sum of all the frequencies must be equal to the number of patients that answered the research. With this in mind we can find the missing value, x.
There were 36 patients that reported no pain.
The equation of the line that you get is:
Where m is the slope and q is the y-intercept; then the slope of y=3x-12 is 3.
Well lets have x be the side perpendicular to the barn. You will have two sides of length "x". Which means the side parallel to the barn has the length of (200 -2x)
So we know the area of the pasture is length * width or x * (200 - 2x)
This means we are seeking to maximize x * (200 - 2x).
This is actually a parabola with zeroes that are at x = 0 and x = 100 which means the vertex is at x = 50.
So when x = 50 > (200 - 2x) = 100
So that means the maximum area of the pasture is 50 * 100 = 5000 square feet.
Answer: 43/19
Step-by-step explanation:
4x−2+3(5x−2+7)=56
Step 1: Simplify both sides of the equation.
4x−2+3(5x−2+7)=56
4x+−2+(3)(5x)+(3)(−2)+(3)(7)=56(Distribute)
4x+−2+15x+−6+21=56
(4x+15x)+(−2+−6+21)=56(Combine Like Terms)
19x+13=56
19x+13=56
Step 2: Subtract 13 from both sides.
19x+13−13=56−13
19x=43
Step 3: Divide both sides by 19.
19/19x=43/19 thus the answer is 43/19
Answer:
Given that Angelo spends the same amount every day from the amount in
the lunch card, the function of the amount remaining is a linear function.
The constant rate of change of the function is; -5.25
The two ordered pairs used to find the constant rate of change are; (1, 44.75) and (2, 39.5)
Reasons:
The amount Angelo's mother put on the lunch card = $50
A possible table of values to the question is presented as follows;
Required:
The constant rate of the function that gives the amount remaining from the
amount Angelo's mother put on his lunch card.
Solution:
The two ordered pairs that can be used to find the slope or constant rate of change are;
(x₁, y₁) = (1, 44.75), and (x₂, y₂) = (2, 39.5)
With the above two ordered pairs, we have the constant rate of change of the function given as follows;
The constant rate of change for the function that gives the amount remaining in the lunch card is; -5.25