Answer:
x = √(-1) = i
Since the value of √(-1) is not real.
The system has no real solution.
Step-by-step explanation:
The solution to the system of equations is at the point where they intercept each other.
y1 = y2
For the given equation;
y=x^2-2x and y=-2x-1
To get the where they intercept, we will equal both equations;
y=x^2-2x = -2x-1
x^2 - 2x = -2x - 1
x^2 - 2x + 2x + 1 =0
x^2 +1 = 0
x^2 = -1
x = √(-1) = i
Since the value of √(-1) is not real.
The system has no real solution.
Answer:
x = - 4 ± 2
Step-by-step explanation:
Given
f(x) = x² + 8x + 4
To find the zeros let f(x) = 0, that is
x² + 8x + 4 = 0 ( subtract 4 from both sides )
x² + 8x = - 4
To solve using the method of completing the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(4)x + 16 = - 4 + 16
(x + 4)² = 12 ( take the square root of both sides )
x + 4 = ± 
= ± 2 ( subtract 4 from both sides )
x = - 4 ± 2
Thus the zeros are
x = - 4 - 2 and x = - 4 + 2
Answer:
True
Step-by-step explanation:
Answer:
x = 23 degrees
Step-by-step explanation:
sin theta = opposite side/ hypotenuse
sin x= 9/23
Take the arcsin of each side
arcsin( sinx) = arcsin (9/23)
x = arcsin (9/23)
x=23.03568411
Rounding to the nearest degree
x = 23 degrees
