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Katyanochek1 [597]
3 years ago
8

In the U.S. More male babies are born than females. In 1998 some 2,265,031 males were born and 2,287,419 females were born. Find

the empirical probability of an individual being born as a boy
Mathematics
2 answers:
azamat3 years ago
4 0

Answer:

0.498 or 49.8%

Step-by-step explanation:

Empirical probability or experimental probability = number of times an event occured/total number of trials.

In this case, the number of times an event (male being born) occured = 2,265,031 and the total number of trials = 2,265,031 males + 2,287,419 females = 4,552,450 individuals.

The Empirical probability of an individual being a boy = 2,265,031/4,552,450

= 0.498 or 49.8%

suter [353]3 years ago
3 0

Answer: The empirical probability that the individual being born is a male = 0.498

Step-by-step explanation:

Given the following :

Number of males born =2,265,031

Number of females born = 2,287,419

Empirical probability is given as :

P( A) =( Number of possible outcomes of event A ÷ Total number of events)

Total number of events = (number of males born + number of females born)

Total number of events = (2,265,031 + 2,287,419) = 4552450

Probability(individual being born is a boy) =

(Number of males born ÷ Total number of children born)

=2265031÷(2265031+2287419) = 0.49754110424057

Therefore, the empirical probability that the individual being born is a male = 0.498

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kherson [118]

Step-by-step explanation:

The equation of a circle can be the expanded form of

\large \text{$(x-a)^2+(y-b)^2=r^2$}(x−a)

2

+(y−b)

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=r

2

where rr is the radius of the circle, (a,\ b)(a, b) is the center of the circle, and (x,\ y)(x, y) is a point on the circle.

Here, the equation of the circle is,

\begin{gathered}\begin{aligned}&x^2+y^2+10x-4y-20&=&\ \ 0\\ \\ \Longrightarrow\ \ &x^2+y^2+10x-4y+25+4-49&=&\ \ 0\\ \\ \Longrightarrow\ \ &x^2+y^2+10x-4y+25+4&=&\ \ 49\\ \\ \Longrightarrow\ \ &x^2+10x+25+y^2-4y+4&=&\ \ 49\\ \\ \Longrightarrow\ \ &(x+5)^2+(y-2)^2&=&\ \ 7^2\end{aligned}\end{gathered}

⟹

⟹

⟹

⟹

x

2

+y

2

+10x−4y−20

x

2

+y

2

+10x−4y+25+4−49

x

2

+y

2

+10x−4y+25+4

x

2

+10x+25+y

2

−4y+4

(x+5)

2

+(y−2)

2

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=

=

=

=

0

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49

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2

From this, we get two things:

\begin{gathered}\begin{aligned}1.&\ \ \textsf{Center of the circle is $(-5,\ 2)$.}\\ \\ 2.&\ \ \textsf{Radius of the circle is $\bold{7}$ units. }\end{aligned}\end{gathered}

1.

2.

Center of the circle is (−5, 2).

Radius of the circle is 7 units.

Hence the radius is 7 units.

4 0
2 years ago
Find the size of one interior angle of a regular pentagon
barxatty [35]

Answer:

The measure of one interior angle of a regular pentagon is 108 degrees.

Step-by-step explanation:

Use a digital ruler.

3 0
3 years ago
interpret r(t) as the position of a moving object at time t. Find the curvature of the path and determine thetangential and norm
Igoryamba

Answer:

The curvature is \kappa=1

The tangential component of acceleration is a_{\boldsymbol{T}}=0

The normal component of acceleration is a_{\boldsymbol{N}}=1 (2)^2=4

Step-by-step explanation:

To find the curvature of the path we are going to use this formula:

\kappa=\frac{||d\boldsymbol{T}/dt||}{ds/dt}

where

\boldsymbol{T}} is the unit tangent vector.

\frac{ds}{dt}=|| \boldsymbol{r}'(t)}|| is the speed of the object

We need to find \boldsymbol{r}'(t), we know that \boldsymbol{r}(t)=cos \:2t \:\boldsymbol{i}+sin \:2t \:\boldsymbol{j}+ \:\boldsymbol{k} so

\boldsymbol{r}'(t)=\frac{d}{dt}\left(cos\left(2t\right)\right)\:\boldsymbol{i}+\frac{d}{dt}\left(sin\left(2t\right)\right)\:\boldsymbol{j}+\frac{d}{dt}\left(1)\right\:\boldsymbol{k}\\\boldsymbol{r}'(t)=-2\sin \left(2t\right)\boldsymbol{i}+2\cos \left(2t\right)\boldsymbol{j}

Next , we find the magnitude of derivative of the position vector

|| \boldsymbol{r}'(t)}||=\sqrt{(-2\sin \left(2t\right))^2+(2\cos \left(2t\right))^2} \\|| \boldsymbol{r}'(t)}||=\sqrt{2^2\sin ^2\left(2t\right)+2^2\cos ^2\left(2t\right)}\\|| \boldsymbol{r}'(t)}||=\sqrt{4\left(\sin ^2\left(2t\right)+\cos ^2\left(2t\right)\right)}\\|| \boldsymbol{r}'(t)}||=\sqrt{4}\sqrt{\sin ^2\left(2t\right)+\cos ^2\left(2t\right)}\\\\\mathrm{Use\:the\:following\:identity}:\quad \cos ^2\left(x\right)+\sin ^2\left(x\right)=1\\\\|| \boldsymbol{r}'(t)}||=2\sqrt{1}=2

The unit tangent vector is defined by

\boldsymbol{T}}=\frac{\boldsymbol{r}'(t)}{||\boldsymbol{r}'(t)||}

\boldsymbol{T}}=\frac{-2\sin \left(2t\right)\boldsymbol{i}+2\cos \left(2t\right)\boldsymbol{j}}{2} =\sin \left(2t\right)+\cos \left(2t\right)

We need to find the derivative of unit tangent vector

\boldsymbol{T}'=\frac{d}{dt}(\sin \left(2t\right)\boldsymbol{i}+\cos \left(2t\right)\boldsymbol{j}) \\\boldsymbol{T}'=-2\cdot(\sin \left(2t\right)\boldsymbol{i}+\cos \left(2t\right)\boldsymbol{j})

And the magnitude of the derivative of unit tangent vector is

||\boldsymbol{T}'||=2\sqrt{\cos ^2\left(x\right)+\sin ^2\left(x\right)} =2

The curvature is

\kappa=\frac{||d\boldsymbol{T}/dt||}{ds/dt}=\frac{2}{2} =1

The tangential component of acceleration is given by the formula

a_{\boldsymbol{T}}=\frac{d^2s}{dt^2}

We know that \frac{ds}{dt}=|| \boldsymbol{r}'(t)}|| and ||\boldsymbol{r}'(t)}||=2

\frac{d}{dt}\left(2\right)\: = 0 so

a_{\boldsymbol{T}}=0

The normal component of acceleration is given by the formula

a_{\boldsymbol{N}}=\kappa (\frac{ds}{dt})^2

We know that \kappa=1 and \frac{ds}{dt}=2 so

a_{\boldsymbol{N}}=1 (2)^2=4

3 0
3 years ago
Suppose a computer manufacturer has the total cost function C(x) = 74x + 3600 (in dollars) and the total revenue function R(x) =
Lemur [1.5K]

The equation of the profit function is 300x - 3600

Total cost function C(x) = 74x + 3600

Total revenue function R(x) = 374x

The profit function is the difference between the total revenue and the total cost and this will be:

= R(x) - C(x)

= 374x - (74x + 3600)

= 374x - 74x - 3600

= 300x - 3600

In conclusion, the equation of the profit function is 300x - 3600

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4 0
2 years ago
What's the equivalent
olga2289 [7]

9 1/2 = 19/2

(29/5) / (19/2)

When changing division to multiplication, flip the number (right hand side).

(29/5) * (2/19)

58/95

7 0
3 years ago
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