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Liono4ka [1.6K]
2 years ago
9

AB with endpoints A(8,-12) and B(4, 10)

Mathematics
1 answer:
kondaur [170]2 years ago
8 0

Answer:

(7,9) , (0,3)

(1, 2) , (2, 9)

(-3, 9) , (0, 9)

Step-by-step explanation:

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A necklace regularly sells for $18.00. the store advertises a 15% discount. what is the sale price of the necklace in dollars
SSSSS [86.1K]
I can solve with 2 methods:

I. Because the discount is 15 % of 18 $ , the price will be (100-15=85) 85 % of 18 $
18*85/100= 15,3 $ ( the sale price)

II. The discount is 15 % of 18$
15*18/100= 2,7$  ( the discount)
then I decrease it from the regularly price
18$-2,7$=15,3 $ (the sale price)

Personally I believe the first is an easier method.
I hope you understand and you can apply this in every similary problem.



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3 years ago
What are the typical null and alternate hypotheses for a significance test on slope?
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I'm sure you should look it up on Google I'm pretty sure that that would help you more than this stupid app OK look it up on Google or a Siri it will help you a lot better
8 0
2 years ago
What is the value of x in the figure Pls help​
Murljashka [212]

Answer: x=18

im assuming that this is a right angle

so if it is then that means the total of the angle should be 90 degrees. so 2x+3x should be equal to 90. Just combine like terms to get that 5x=90 and then isolate the variable (divide by 5 on both sides) so x ends up equaling 18.

so x=18

7 0
3 years ago
What is b-1 over b-1
diamong [38]

Answer:

what?Can you write better?

8 0
2 years ago
Find the least common multiple of these two expressions. 15x^7y^3u^8 and 6y^4u^5
snow_tiger [21]

Answer:

30x^7y^4u^8

Step-by-step explanation:

We have been given two expressions 15x^7y^3u^8 and

6y^4u^5

Now we need to find out least common multiple of these two expressions.

First we need to find out what is common factor of both expressions. 15x^7y^3u^8 and

6y^4u^5

Least common multiple means find the expression which can be divided by both expressions.

15 and 6 both goes into 30

so 30 is part of LCM (least common multiple )

Now pickup the highest exponent of each variable.

So we get x^7y^4u^8

Hence required least common multiple is 30x^7y^4u^8

8 0
3 years ago
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