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deff fn [24]
3 years ago
9

9. Michelle likes chocolate but it causes acne. She chooses to limit herself to three chocolate bars every 5 days. (So, she eats

part of a bar each day.)
Arithmetic or geometric?

Recursive:

Explicit:​
Mathematics
1 answer:
OverLord2011 [107]3 years ago
4 0

Answer:

Arithmetic

An = A[n - 1] + 3/5

An = 3/5[n]

Step-by-step explanation:

Number of days = 5

Number of chocolate = 3

Computation:

Recursive:

Number of chocolate eat per day = 3/5

So,

First term a1 = 3/5

So,

An = A[n - 1] + 3/5

Explicit:​

An = 3/5 + 3/5[n-1]

An = 3/5[n]

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Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of ?
Darina [25.2K]

Answer:

y – 2 = (x – 3)

Step-by-step explanation:

because (3, 2) was the point used for the equation but turned negative because you need to make it negative for the equation. y - y1 =m(x - x1)

4 0
3 years ago
Your interest rate is compounded annually. Beginning Balance: $1,166.40. Annual Interest Rate: 8% How much will you earn in inte
konstantin123 [22]

Answer:

93.31200 dollars

Step-by-step explanation:

8% of 1166.40

4 0
3 years ago
Are is 16/14 and 64/60
zalisa [80]
Do you know how to solve this??
6 0
3 years ago
Any REAL help on #16 above??? Can someone check my answer?
babymother [125]

Answer:

The answer to your question is:th first option is correct.

Step-by-step explanation:

Here we have and hyperbola with center (0, 1), and the hyperbola is horizontal because x² is positive.

Equation

y - k = ±\frac{b}{a} (x - h)

Process

Find a, b

                a² = 9    

               a = 3

                b² = 5

              b = √5

              h = 0    and k = 1

Substitution

              y - 1 = ±\frac{√5}{3} (x - 0)

Equation 1

            y = \frac{\sqrt{5} }{3} x + 1

Equation 2

           y = - \frac{\sqrt{5} }{3} x + 1  

3 0
3 years ago
Da<br> A<br> Solve the equation 2x^2+3=0
Anika [276]

Answer:

x = ±i(√6 / 2)

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Algebra I</u>

  • Solving quadratics

<u>Algebra II</u>

Imaginary root i

  • √-1 = i

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

2x² + 3 = 0

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Subtraction Property of Equality] Subtract 3 on both sides:                        2x² = -3
  2. [Division Property of Equality] Divide 2 on both sides:                                  x² = -3/2
  3. [Equality Property] Square root both sides:                                                    x = ±√(-3/2)
  4. Simplify:                                                                                                             x = ±i(√6 / 2)
4 0
3 years ago
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