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Lady bird [3.3K]
4 years ago
12

For a given input value nnn, the function ggg outputs a value mmm to satisfy the following equation.

Mathematics
2 answers:
Mademuasel [1]4 years ago
4 0

For a given input value n, the function g outputs a value m to satisfy the following equation.

3m-5n=11

Write a formula for g(n), in terms of n.

g(n)=

Answer:

3m-5n=11

the function g outputs a value m. It means we need to solve for m in terms of n

solve the given equation for m

3m-5n=11

Inverse of -5n is +5n so we add 5n on both sides

3m-5n + 5n=11 + 5n

3m = 11 + 5n

Divide by 3 on both sides

m = \frac{11+5n}{3}

The function g outputs the value m

So g(n) = \frac{11+5n}{3}

fomenos4 years ago
3 0

Answer:-

f(u)=-4v+9

Step-by-step explanation:

u-5=-4(v-1)

u=-4(v-1)+5

v= -4v+9

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A rectangular pan has a length that is the width. The total area of the pan is 432 in.2. What is the width of the cake pan? A =
spayn [35]

Answer:

Let width = w

length = 4w/3

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4 0
3 years ago
We learned in that about 69.7% of 18-20 year olds consumed alcoholic beverages in 2008. We now consider a random sample of fifty
maw [93]

Answer:

(1) The expected number of people who would have consumed alcoholic beverages is 34.9.

(2) The standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3) It is surprising that there were 45 or more people who have consumed alcoholic beverages.

Step-by-step explanation:

Let <em>X</em> = number of adults between 18 to 20 years consumed alcoholic beverages in 2008.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.697.

A random sample of <em>n</em> = 50 adults in the age group 18 - 20 years is selected.

An adult, in the age group 18 - 20 years, consuming alcohol is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 50 and <em>p</em> = 0.697.

The probability mass function of a Binomial random variable <em>X</em> is:

P(X=x)={50\choose x}0.697^{x}(1-0.697)^{50-x};\ x=0,1,2,3...

(1)

Compute the expected value of <em>X</em> as follows:

E(X)=np\\=50\times 0.697\\=34.85\\\approx34.9

Thus, the expected number of people who would have consumed alcoholic beverages is 34.9.

(2)

Compute the standard deviation of <em>X</em> as follows:

SD(X)=\sqrt{np(1-p)}=\sqrt{50\times 0.697\times (1-0.697)}=10.55955\approx10.56

Thus, the standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3)

Compute the probability of <em>X</em> ≥ 45 as follows:

P (<em>X</em> ≥ 45) = P (X = 45) + P (X = 46) + ... + P (X = 50)

                =\sum\limits^{50}_{x=45} {50\choose x}0.697^{x}(1-0.697)^{50-x}\\=0.0005+0.0001+0.00002+0.000003+0+0\\=0.000623\\\approx0.0006

The probability that 45 or more have consumed alcoholic beverages is 0.0006.

An unusual or surprising event is an event that has a very low probability of success, i.e. <em>p</em> < 0.05.

The probability of 45 or more have consumed alcoholic beverages is 0.0006. This probability value is very small.

Thus, it is surprising that there were 45 or more people who have consumed alcoholic beverages.

6 0
3 years ago
What is the approximate curcumfrance of the circle shown below?​
Vikki [24]

Answer:

C.

Step-by-step explanation:

Circumference=PI*diameter

Circumference=3.14*19.5

Circumference=61.23 rounds to 61.2 so the answer is C

3 0
3 years ago
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