Consider the graph that represents the following quadratic equation y=-1/3(x+2)^2+5
1 answer:
We have that
<span>y=-1/3(x+2)</span>²<span>+5
using a graph tool
see the attached figure
we know that
1) the graph open downward
2) the vertex of the graphic is the point (-2,5)
3) the axis of symmetry of the graph is x=-2
4) the x intercept values are (-5.873,0) and (1.873,0)
5) the y intercept value is (0,3.667)
</span><span>
</span>
<span>y=-1/3(x+2)</span>²<span>+5
using a graph tool
see the attached figure
we know that
1) the graph open downward
2) the vertex of the graphic is the point (-2,5)
3) the axis of symmetry of the graph is x=-2
4) the x intercept values are (-5.873,0) and (1.873,0)
5) the y intercept value is (0,3.667)
</span><span>
</span>
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Answer:
In order to find the slope (m), and the y-intercept of this coordinate pair, you must complete rise over run.
This is represented by y2-y1, x2-x1. This can be represented like so:
-4-0 = -4
5--4 = 9
Here, we have concluded that our slope is -4/9.
Now, we must convert this into point slope form. Point slope form is y-y1=m(x-x1). This will look like this in our situation:
y+4=-4/9(x-0)
To solve, distribute the -4/9 first, which will leave you with:
y+4=-4/9x+0
Now, subract the 4 to both sides of the equation.
Our final answer looks like: y=-4/9-4.
<em>-</em>
<em>SLOPE: -4/9</em>
<em>Y INTERCEPT: -4 </em>
