Answer:
Step-by-step explanation:
$ 8 admission and $ 2 a ride
y = 2x + 8.....where y is the total cost and x is the # of rides
table :
x = 1 , 2 , 3 , 4 ,5 , 6
y = 10, 12 , 14, 16 , 18 , 20
Using the distance formula,


Since ABCD has two pairs of opposite congruent sides, it is a parallelogram.
Answer: Choice C)
We start at 0 and move 1.4 units to the right. Then we move another 2.3 units to the right to land on 3.7
Notice how 1.4 - (-2.3) = 1.4 + 2.3 = 3.7
Answer:
Anything in the form x = pi+k*pi, for any integer k
These are not removable discontinuities.
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Explanation:
Recall that tan(x) = sin(x)/cos(x).
The discontinuities occur whenever cos(x) is equal to zero.
Solving cos(x) = 0 will yield the locations when we have discontinuities.
This all applies to tan(x), but we want to work with tan(x/2) instead.
Simply replace x with x/2 and solve for x like so
cos(x/2) = 0
x/2 = arccos(0)
x/2 = (pi/2) + 2pi*k or x/2 = (-pi/2) + 2pi*k
x = pi + 4pi*k or x = -pi + 4pi*k
Where k is any integer.
If we make a table of some example k values, then we'll find that we could get the following outputs:
- x = -3pi
- x = -pi
- x = pi
- x = 3pi
- x = 5pi
and so on. These are the odd multiples of pi.
So we can effectively condense those x equations into the single equation x = pi+k*pi
That equation is the same as x = (k+1)pi
The graph is below. It shows we have jump discontinuities. These are <u>not</u> removable discontinuities (since we're not removing a single point).
Answer:
C
Step-by-step explanation:
note that sin x = cos(90 - x ) ← Cofunction identity
If x = 36 then 90 - x = 90 - 36 = 54
Hence sin 36° = cos 54° → C