3 years ago

What is 8 and 1/8 + 40 and 5/8

Mathematics

1 answer:

inna [77]3 years ago

4 0

1x40x5/8
40x5/8
5x5
25

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1. 2X + 1 = Y<br> 2Y = 6<br> Show your work

slamgirl [31]

Answer:

x = 1

y = 3

Step-by-step explanation:

2x + 1 = y ------- eqn (1)

2y = 6--------eqn (2)

from eqn(2)

2y = 6

y = 3

when you divide 6 by 2y

substitute y = 3 into eqn (1)

2x + 1 = y

2x + 1 = 3

2x = 3-1

2x = 2

therefore

x = 1

4 0

3 years ago

Nadir saves $1 the first day of a month, $2 the second day, $4 the third day, and so on. He continues to double his savings each

zheka24 [161]

ANSWER

$16,384

EXPLANATION

From the question we have that,

Nadir saves $1 the first day of a month, $2 the second day, $4 the third day, and so on.

This forms a geometric sequence,

$1,2,4,...$

The first term of this sequence is

$a = 1$

The common ratio is

$r = \frac{2}{1} = \frac{4}{2} = 2$

The general term of a geometric sequence is given by the formula:

$f(n) = a {r}^{n - 1}$

To find the 15th term, we plug in a=1, r=2 and n=15.

$f(15) = 1 {(2)}^{15 - 1}$

$f(15) = {2}^{14}$

$f(15) = 16384$

The amount he will save on the 15th day is $16,384

4 0

3 years ago

Simplify the following expression completely, where x is greater than or equal too 0.

Dennis_Churaev [7]

First you want the numbers under the radical to be the same so you can combine like terms.

$x \sqrt{5xy^4} =x \sqrt{5x*^4y} = xy^2 \sqrt{5x}$
$\sqrt{405x^3y^4} = \sqrt{5x*81x^2y^4} =9xy^2 \sqrt{5x}$
$\sqrt{80x^3y^4} = \sqrt{5x*16x^2y^4} = 4xy^2 \sqrt{5x}$

Now add together to get $14xy^2 \sqrt{5x}$