Answer:
The original function was transformed by a a horizontal shift to the right in 1 unit, and also a vertical shift upwards of 5 units.
Step-by-step explanation:
Recall the four very important rules regarding translations (shifts) of the graph of functions:
1) In order to shift the graph of a function vertically c units upwards, we must transform f (x) by adding c to it.
2) In order to shift the graph of a function vertically c units downwards, we must transform f (x) by subtracting c from it.
3) In order to shift the graph of a function horizontally c units to the right, we must transform the variable x by subtracting c from x.
4) In order to shift the graph of a function horizontally c units to the left, we must transform the variable x by adding c to x.
We notice that in our case, The original function 
has been transformed by "subtracting 1 unit from x", and by adding 5 units to the full function. Therefore we are in the presence of a horizontal shift to the right in 1 unit (as explained in rule 3), and also a vertical shift upwards of 5 units (as explained in rule 1).
Ok, so the quadratic coefient is 1, so great
take 1/2 of the linear coefient and square it
10/2=5, (5)^2=25
add that to both sides
x^2+10x+25=7+25
factor perfect square trionomial
(x+5)^2=32
squaer root both sides
x+5=+/-4√2
minus 5
x=-5+/-4√2
x=-5+4√2 and -5-4√2
Answer:
ali probley has a 50% chance
Step-by-step explanation:
Answer:
Below.
Step-by-step explanation:
15+10+8=33.
Center: (-5,-6)
Radius: 39
How to do it
Complete the square for
y
2
+
12
y
y
2
+
12
y
.
(
y
+
6
)
2
−
36
(
y
+
6
)
2
-
36
Substitute
(
y
+
6
)
2
−
36
(
y
+
6
)
2
-
36
for
y
2
+
12
y
y
2
+
12
y
in the equation
(
x
+
5
)
2
+
y
2
+
12
y
=
3
(
x
+
5
)
2
+
y
2
+
12
y
=
3
.
(
x
+
5
)
2
+
(
y
+
6
)
2
−
36
=
3
(
x
+
5
)
2
+
(
y
+
6
)
2
-
36
=
3
Move
−
36
-
36
to the right side of the equation by adding
36
36
to both sides.
(
x
+
5
)
2
+
(
y
+
6
)
2
=
3
+
36
(
x
+
5
)
2
+
(
y
+
6
)
2
=
3
+
36
Add
3
3
and
36
36
.
(
x
+
5
)
2
+
(
y
+
6
)
2
=
39
(
x
+
5
)
2
+
(
y
+
6
)
2
=
39
This is the form of a circle. Use this form to determine the center and radius of the circle.
