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DochEvi [55]
3 years ago
6

Show all work. What are the zeros of the function? f(x) = 2x^2 − 8x − 10

Mathematics
1 answer:
vivado [14]3 years ago
3 0
(2x² - 8x - 10) ÷ 2 = 0
x² - 4x - 5 = 0
x² + x - 5x - 5 = 0
x(x+1) - 5(x+1) = 0
(x+1)(x-5) = 0
x+1 = 0 or x-5 = 0
x = -1 or x= 5

S = {-1;5}

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<em><u>Solution:</u></em>

Given that we have to simplify the expression shown below

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Let us first convert 0.00048 to scientific notation

<em><u>Steps to follow:</u></em>

Move the decimal point in your number until there is only one non-zero digit to the left of the decimal point. The resulting decimal number is a.

Count how many places you moved the decimal point. This number is b.

If you moved the decimal to the left b is positive.

If you moved the decimal to the right b is negative.

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