Answer:
5 more hours i think i might be wrong
Step-by-step explanation:
What I would do is break up into part. First do 10*10*10 which is 1,000. Then add 56 and 50 which is 106. after you do that and get 1,106 divded it by 25 which is 42.54. Hope I helped.
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<span>You are given the waiting times between a subway departure schedule and the arrival of a passenger that are uniformly distributed between 0 and 6 minutes. You are asked to find the probability that a randomly selected passenger has a waiting time greater than 3.25 minutes.
Le us denote P as the probability that the randomly selected passenger has a waiting time greater than 3.25 minutes.
P = (length of the shaded region) x (height of the shaded region)
P = (6 - 3.25) * (0.167)
P = 2.75 * 0.167
P = 0.40915
P = 0.41</span><span />
Answer:
60 km/h
Step-by-step explanation:
60/40=1.5
90/1.5=60