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2 years ago

Find the missing angle

Mathematics

2 answers:

alexgriva [62]2 years ago

4 0

Answer:

70 degrees

Step-by-step explanation:

60 + 50 + x= 180

60 -60 +50 +x =180-60

50 -50 + x = 120 - 50

x = 70 degrees

Agata [3.3K]2 years ago

3 0

Answer:

70°

Step-by-step explanation:

The sum of triangle is 180

50+60+X= 180

110+X= 180

X= 180-110

X= 70

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HELP its urgent.............

irga5000 [103]

Answer:

first blank = 39

second blank = 28

Step-by-step explanation:

11 + __ + 7 + 28 = 85 = 39 + __ + 11+ 7

since,, four terms add upto form 85 out of which two terms (11 and 7) are common. so, the first blank will be filled with 39 and second blank with 28.

8 0

2 years ago

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If m∠JKM = 43, m∠MKL = (8 - 20), and m∠JKL = (10x - 11), find each measure.

Brut [27]

Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.

1. x = ?

2. m∠MKL = ?

3. m∠JKL = ?

Answer/Step-by-step explanation:

Given:

m<JKM = 43,

m<MKL = (8x - 20),

m<JKL = (10x - 11).

Required:

1. Value of x

2. m<MKL

3. m<JKL

Solution:

1. Value of x:

m<JKL = m<MKL + m<JKM (angle addition postulate)

Therefore:

$(10x - 11) = (8x - 20) + 43$

Solve for x

$10x - 11 = 8x - 20 + 43$

$10x - 11 = 8x + 23$

Subtract 8x from both sides

$10x - 11 - 8x = 8x + 23 - 8x$

$2x - 11 = 23$

Add 11 to both sides

$2x - 11 + 11 = 23 + 11$

$2x = 34$

Divide both sides by 2

$\frac{2x}{2} = \frac{34}{2}$

$x = 17$

2. m<MKL = 8x - 20

Plug in the value of x

m<MKL = 8(17) - 20 = 136 - 20 = 116°

3. m<JKL = 10x - 11

m<JKL = 10(17) - 11 = 170 - 11 = 159°

3 0

2 years ago

Simplify and express the result in power notation with positive exponent

Molodets [167]

Answer:

3²

Step-by-step explanation:

Given expression:

$\sf (3^{-3} \div 3^{-10}) \times 3^{-5}$

Following the <u>order of operations</u>, carry out the calculations inside the parentheses first.

$\textsf{Apply the quotient exponent rule} \quad a^b \div a^c=a^{b-c}:$

$\implies \sf 3^{-3-(-10)} \times 3^{-5}$

$\implies \sf 3^{-3+10} \times 3^{-5}$

$\implies \sf 3^{7} \times 3^{-5}$

$\textsf{Apply the product exponent rule} \quad a^b \times a^c=a^{b+c}:$

$\sf \implies 3^{7+(-5)}$

$\sf \implies 3^{7-5}$

$\sf \implies 3^2$

Learn more about exponent rules here:

brainly.com/question/27959936

brainly.com/question/24947526

4 0

1 year ago

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Help please I need help

lukranit [14]

The answer is Radical 6.

This is because if you use Cosine and the angle measured 30. You would put adjacent over hypotenuse, which is
Cos (30) = X/radical 8

Put this into your calculator to get Radical 6

8 0

2 years ago

For the 2015 Intel Science Fair, two brothers in high school recruited 47 of their classmates to take part in a two-stage study.

kvv77 [185]

Answer:

a) 47

b) 3

c) 1

d) 2

e) 47

f) 3

Step-by-step explanation:

read the textbook

8 0

3 years ago

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