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lord [1]
3 years ago
9

Easter Island is a small island in the southern Pacific Ocean. It lies approximately 3,500 kilometers east of Chile and is consi

dered one of the most remote islands. It is also a volcanic island. In 2025, Easter Island had a population of 16,000. However, many of the island’s residents were killed during a series of volcanic eruptions that occurred in the year 2065. Of the original population, only 200 people survived. It is now 100 years later, and the population of Easter Island has reached 800. Of the current population, 328 people are homozygous recessive for Marfan syndrome, which is autosomal (mm genotype). Marfan syndrome is a genetic disorder that affects the connective tissue. Symptoms of Marfan syndrome include increased height, thinness, flexible joints, heart complications, and long arms, legs, fingers, and toes.
q^2 -
q -
p -
p^2 -
2pq -
Use this information to help you answer the following questions:
The original population’s actual genotype frequencies were: MM – 0.42, Mm – 0.13, mm – 0.45.
1.) Is the current population in Hardy - Weinberg equilibrium? Yes or No
2.) Is the current population evolving? Yes or No
3.) If the current population is evolving, what type of effect is responsible for genetic drift?
Biology
1 answer:
mestny [16]3 years ago
4 0

Answer:

Explanation:Define as it relates to adaptation

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Yeast is used to make the bread soft and fluffy . Yeast cells thrive on simple sugars . As the sugars are metabolized , Carbon dioxide and alcohol are released into the bread dough making it rise . So the bread becomes soft and fluffy. The baker made great bread.

Explanation:

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A scientist is studying the action of RNA polymerase during transcription. He wants to know what type of bases are added to the
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How do glow sticks light up in the dark?
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4 0
3 years ago
Suppose a species of bird called the red-crested warbler has a plumage length that is controlled by a single gene. The Plm allel
AleksAgata [21]

We are going to have different allele frequencies for the two populations

North American:

72 birds total => 144 alleles

72 - 55 birds = 17 short plume birds.

q^2 = (2*17) / 114 = 0.236

Freq(short plume allele) = q = 0.486

Freq(long plume allele) = p = 1 - q = 0.514

From this North American population we get

0.486 * 114 = 55 long plume alleles

0.514 * 114 = 59 short plume alleles

South American:

252 birds total => 504 alleles

252 - 75 birds = 177 short plume birds.

q^2 = (2*177) / 504 = 0.702

Freq(short plume allele) = q = 0.838

Freq(long plume allele) = p = 1 - q = 0.162

From this South American population we get

0.162 * 504 = 82 long plume alleles

0.838 * 504 = 422 short plume alleles

Blended population has

55 + 82 = 137 long plume alleles

59 + 422 = 481 short plume alleles

137 + 481 = 618 total alleles

p = 137/618 = 0.222

q = 481/618 = 0.778

The new population has the p and q from the blended population. The new population has 1000 individuals. The portion of long plumed will be homozygote long plumage + heterozygote, which is p^2 + 2pq, and you multiply that by the population size 1000 to get the final answer.

population size * (p^2 + 2pq) = 1000 * (0.222^2 + 2*0.222*0.778) = 395 birds (answer)

6 0
3 years ago
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