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2 years ago

PLEASE HELP ASAP 15 POINTS

Mathematics

1 answer:

stepan [7]2 years ago

5 0

Answer: Its C

Step-by-step explanation: Hope this Helped!!!

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In the complex number system, which of the following is equal to

pogonyaev

Answer:

C) $122+154i$

Step-by-step explanation:

$(14-2i)(7+12i)\\\\(14)(7)+(14)(12i)+(-2i)(7)+(-2i)(12i)\\\\98+168i-14i-24i^2\\\\98+154i-24(-1)\\\\98+154i+24\\\\122+154i$

Therefore, C is correct. Recall that $i^2=-1$

3 0

2 years ago

Read 2 more answers

Simplify <br> (0.5)2+3.5divided by 5

patriot [66]

Answer:

2.7

Step-by-step explanation:

7 0

2 years ago

Find the interest earned in an account with $600 invested at 4.5% annual simple interest for 2 years.

astra-53 [7]

Answer:

40%

Step-by-step explanation:

every year the interested be 20%

that's why in 2 years be 40%interest

3 0

2 years ago

Solve 0.05p-0.02(5-2p)=0.05(p-2)-0.12

Montano1993 [528]

$0.05p-0.02(5-2p)=0.05(p-2)-0.12$

$0.05p-0.02(5-2p)=0.05(p-2)-0.12:p$

$
0.05p-0.1+0.04p=0.05p-0.1-0.12
 
$ $|Expand \ the \ equation|$

$0.09p-0.1=0.05p-0.1-0.12
 
$

$0.09p-0.1=0.05p-0.22$

$
0.09p-0.1-0.05p=-0.22
 

$ $|Subtract \ 0.05p \ from \ both \ sides|$

$
0.04p-0.1=-0.22
 
$

$
0.04p=-0.22+0.1
 
$ $|Add \ 0.1 \ to \ both \ sides|$

$
0.04p=-0.12
 
$

$0.04p/0.04=-0.12/0.04
$ $|Divide \ both \ sides \ by \ 0.04|$

$p=-3$

$\star \ Hence \ Solved$

8 0

2 years ago

Assume that 33.4% of people have sleepwalked. Assume that in a random sample of 1459 adults, 526 have sleepwalked.

lutik1710 [3]

Answer:

Step-by-step explanation:

Given that 33.4% of people have sleepwalked.

Sample size n =1459

Sample favourable persons = 526

Sample proportion p = $\frac{526}{1459} \\=0.361$

Sample proportion p is normal for large samples with mean = 0.334 and

std error = $\sqrt{\frac{pq}{n} } \\=\sqrt{\frac{0.334(1-0.334)}{1459} } \\=0.0123$

a) P(526 or more of the 1459 adults have sleepwalked.)

$=P(p\geq 0.361)\\=P(Z\geq \frac{0.361-0.334}{0.0123} \\=P(Z\geq 2.20)\\=0.5-0.4861\\=0.0139$

b) Yes, because hardly 1.4% is the probability

c) 33.4 is very less compared to the average. Either sample should be improved representing the population or population mean should be increased accordingly.

7 0

2 years ago