Answer:
D) Yes, it is important that the single-stranded DNA have 3′ ends, so resection must occur in the 5′ to 3′ direction.
Explanation:
During homologous recombination, the exonucleases remove nucleotides from the free 5' ends of the DNA at the double-stranded breaks to create a double-strand gap.
Removal of more nucleotides from the free 5' ends creates 3' single-strand extension which in turn invades the intact homolog and pairs with its complementary sequence of the DNA. The invaded free 3' end is then extended by DNA polymerase to give rise to Holiday junctions.
If the resection occurs in the opposite direction and creates overhangs with free 5' ends, the free 3' ends would not be available to serve as a primer to facilitate the replication.
Answer:
The correct answer is D. Immigration is when animals move into an ecosystem.
Explanation:
Animal migration is the movement of animals from one habitat to another, caused by specific needs for food, hibernation, climatic issues, or even to escape predators. Migration, like the migration of birds, is a directed migration, that is, it aims at a specific end; while dispersion is the more or less random distribution of a group of individuals over the habitat. Thus, within the migratory process of animals, two movements are distinguished: emigration, which is the departure of animals from a place, and immigration, which is the entry or arrival of these to the new habitat.
What happens in the ribosome during the process of translation?
- DNA replicates itself
Explanation:
The genetic information stored in DNA is a living archive of instructions that cells use to accomplish the functions of life.

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Answer:
The smallest size tube that will hold the entire reaction is 0.5ml
Explanation:
25ul (DNA sample) + 25ul (enzyme) + 50ul (buffer) + 400ul (water) = 500ul total
since 1000ul=1ml, then 500ul = 0.5ml
Answer:
The device that mostlikely would not be used P20
Explanation:
P20 is a pipette used to measure and sample volumes of 20ul maximum.
Answer:
The reaction mix will have 400 units of the enzyme.
The working dilution will be 0.8 Units/ul.
Explanation:
The mix has 20ul of the enzyme which is 20Units/ul. Then we have 20ulx20Units/ul= 400 Units of enzyme in the mix.
Since the final volume is 500ul, the final concentration 400Units/500ul=0.8 Units/ul.
The third option, "other fungi growth".