Question

Easy question

Answer 1

If for $x$ cumulative frequency the marks are $y$ (as given on the graph), we have $x$ students with marks equal to or less than $y$

d)

Total students are $140$. Hence three-fifths of that is $140\times \frac{3}{5}=84$. Find the marks at $84$ in the graph for the passing marks.

e)

From the graph we have $60$ students having less than or equal to $30$ marks. Total students are $140$.

Subtracting, $140-60=80$ we get the numbee of students achieving more than 30 marks.

Answer 2

Answer:

d)33

e)80

Step-by-step explanation:

I'm sorry I don't really know how to explain this.