Easy question
2 answers:
If for cumulative frequency the marks are $y$ (as given on the graph), we have $x$ students with marks equal to or less than $y$
d)
Total students are $140$. Hence three-fifths of that is $140\times \frac{3}{5}=84$. Find the marks at $84$ in the graph for the passing marks.
e)
From the graph we have $60$ students having less than or equal to $30$ marks. Total students are $140$.
Subtracting, $140-60=80$ we get the numbee of students achieving more than 30 marks.
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<h2>Answer:</h2><h2>If she continues to throw darts 75 more times, she could predict to hit the
</h2><h2>bull's-eye 15 times.</h2>
Step-by-step explanation:
Shay found that she hit the bull's-eye when throwing darts times =
.
In five times, she will hit the dart once.
If she continues to throw darts 75 more times,
the probability that she will hit the bull's eye = (75) = 15 times.
If she continues to throw darts 75 more times, she could predict to hit the
bull's-eye 15 times.