2 answers:
If for 
cumulative frequency the marks are $y$ (as given on the graph), we have $x$ students with marks equal to or less than $y$
d)
Total students are $140$. Hence three-fifths of that is $140\times \frac{3}{5}=84$. Find the marks at $84$ in the graph for the passing marks.
e)
From the graph we have $60$ students having less than or equal to $30$ marks. Total students are $140$.
Subtracting, $140-60=80$ we get the numbee of students achieving more than 30 marks.
Answer:
d)33
e)80
Step-by-step explanation:
I'm sorry I don't really know how to explain this.
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74
Step-by-step explanation:
(80+96+81+89+64)÷5 = 84
Used the formula to get the average of a number. Hope this helps
Answer:
angles in a triangle add up to 180°
5:12:13 = 30
180 ÷ 30 = 6
6 × 5 = 30°
6 × 12 = 72°
6 × 13 = 78°
angles = 30°, 72°, 78°
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I would say A (7) but I’m not 100% sure.
