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3 years ago

I need helppppppp plzzzzzz

Mathematics

2 answers:

Zanzabum3 years ago

3 0

14 x 10^3 = 14,000 (the elephants weight)

So the cat weighs 14 pounds

andre [41]3 years ago

3 0

<em>Answer,</em>

<em>Explanation,</em>

C x 10^3 = 14,000

<em>Solve for C</em>

C = 14

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At a football game, 12 people are wearing red jerseys and 15 people are wearing white jerseys. Write the ratio of red to white j

Anastasy [175]

Answer:

12:15 (simplified: 4:5)

12/15 (simplified: 4/5)

12 to 15 (simplified: 4 to 5)

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6 0

2 years ago

Read 2 more answers

Find 40% of 28. Use a fraction

Schach [20]

=40/100×28
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7 0

2 years ago

Kathy is baking cakes. Each cake requires 1/12 of a teaspoon of vanilla, and she has 9/12 of a teaspoon, how many cakes can she

kati45 [8]

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3 years ago

Solve the system by using a matrix equation (Picture provided)

Katyanochek1 [597]

Answer:

Option b is correct (8,13).

Step-by-step explanation:

7x - 4y = 4

10x - 6y =2

it can be represented in matrix form as $\left[\begin{array}{cc}7&-4\\10&-6\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}4\\2\end{array}\right]$

A= $\left[\begin{array}{cc}7&-4\\10&-6\end{array}\right]$

X= $\left[\begin{array}{c}x\\y\end{array}\right]$

B= $\left[\begin{array}{c}4\\2\end{array}\right]$

i.e, AX=B

or X= A⁻¹ B

A⁻¹ = 1/|A| * Adj A

determinant of A = |A|= (7*-6) - (-4*10)

= (-42)-(-40)

= (-42) + 40 = -2

so, |A| = -2

Adj A= $\left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]$

A⁻¹ = $\left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]$ / -2

A⁻¹ = $\left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right]$

X= A⁻¹ B

X= $\left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right] *\left[\begin{array}{c}4\\2\end{array}\right]$

X= $\left[\begin{array}{c}(3*4) + (-2*2)\\(5*4) + (-7/2*2)\end{array}\right]$

X= $\left[\begin{array}{c}12-4\\20-7\end{array}\right]$

X= $\left[\begin{array}{c}8\\13\end{array}\right]$

x= 8, y= 13

solution set= (8,13).

Option b is correct.

3 0

3 years ago

A hypothesis will be used to test that a population mean equals 10 against the alternative that the population mean is more than

PilotLPTM [1.2K]

Answer:

A) 2.58

B) 1.96

C) 1.65

Step-by-step explanation:

A hypothesis used to test that

$H_o : \mu = 10$

against the alternatives $H1 : \mu$ not equal to 10

if null hypothesis is true, then distribution of test statics follow

$Zo = \frac{\bar x - \mu}{\frac{\sigma}{\sqrt{n}}}$

for two sided alternatives hypothesis $( H1: \mu \neq 7)$ , then P value is

$P = 2[1- \phi(\left | Zc \right |)]$ (1)

a)significance level $\alpha = 0.01$

from 1 eq we get

$\pi (\left | Zc \right |) = P(Zo$

Therefore $\left | Zc \right | = 2.58$ FROM Z TABLE

B) significance level $\alpha = 0.05$

from 1st equation we get

$\pi (\left | Zc \right |) = P(Zo < \left | Zc \right |) = 1 - \frac{0.05}{2} = 0.975$

Therefore $\left | Zc \right | = 1.96$ FROM Z TABLE

C) significance level $\alpha = 0.10$

from 1 eq we get

$\pi (\left | Zc \right |) = P(Zo$

Therefore $\left | Zc \right | = 1.65$ FROM Z TABLE

3 0

3 years ago