Question 3 of 10
1 answer:
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Answer:
Step-by-step explanation:
The summary of the given statistics data include:
sample size n = 400
sample mean = 6.86
standard deviation = 4.37
Level of significance ∝ = 0.01
Population Mean = 6.00
Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
To start with the hypothesis;
The null and the alternative hypothesis can be computed as :
The test statistics for this two tailed test can be computed as:
z = 3.936
degree of freedom = n - 1
degree of freedom = 400 - 1
degree of freedom = 399
At the level of significance ∝ = 0.01
P -value = 2 × (z < 3.936) since it is a two tailed test
P -value = 2 × ( 1 - P(z ≤ 3.936)
P -value = 2 × ( 1 -0.9999)
P -value = 2 × ( 0.0001)
P -value = 0.0002
Since the P-value is less than level of significance , we reject at level of significance 0.01
Conclusion: There is sufficient evidence to conclude that the original claim that the mean of the population of earthquake depths is 5.00 km.
Answer:
25% of 30% of 400 = 30
33% decrease in value
Step-by-step explanation:
You can either get 30% of 400 first then 25% of 400 or you can get the total percentage of 400.
Method 1:
30% of 400 = 0.3 of 400 = 0.3 * 400 = 120
25% of 120 = .25 of 120 = .25 * 120 = 30
Method 2:
30% of 25% = 0.3 * 0.25 = 0.075 = 7.5% of 400
7.5% of 400 = 0.075 of 400 = 0.075 * 400 = 30
5.) To find the percentage of the new price, you can build the equation below.
The percentage decrease in price is then 100% of the original price - 66.667% of the original price = 100% - 66.67% = 33.33% = 33% decrease.