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Marizza181 [45]
3 years ago
8

Find the 4th term (x-y)^12

Mathematics
1 answer:
maria [59]3 years ago
3 0

Answer:

The fourth term of the expansion is -220 * x^9 * y^3

Step-by-step explanation:

Question:

Find the fourth term in (x-y)^12

Solution:

Notation: "n choose k", or combination of k objects from n objects,

C(n,k) = n! / ( k! (n-k)! )

For example, C(12,4) = 12! / (4! 8!) = 495

Using the binomial expansion formula

(a+b)^n

= C(n,0)a^n + C(n,1)a^(n-1)b + C(n,2)a^(n-2)b^2 + C(n,3)a^(n-3)b^3 + C(n,4)a^(n-4)b^4 +....+C(n,n)b^n

For (x-y)^12, n=12, k=3, a=x, b=-y, and the fourth term is

C(n,3)a^(n-3)b^3

=C(12,3) * x^(12-3) * (-y)^(3)

= 220*x^9*(-y)^3

= -220 * x^9 * y^3

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The answer is -16 - 10i.

Using the distributive property on the first part, we have:
-2i*7--2i*4i + (3+i)(-2+2i)
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Using FOIL on the last part,
-14i+8i²+(3*-2+3*2i+i*-2+i*2i)
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Since we know that i = -1,
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Step-by-step explanation:

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Determine the greatest common factor of 15xy^7z and 30x^2y^7z
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Answer:

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Step-by-step explanation:

<h3>Factorize the Expressions</h3>

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<h3>Factor out the Common Factors</h3>

gcf = 3 \times 5 \times x \times y \times y \times y \times y \times y \times y \times y \times z

<h3>Multiply the Common Factors</h3>

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