Which shows the pre-image of triangle X'Y'Z' before the figure was rotated 90° about the origin?
2 answers:
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Answer: choice B) yes; only one range value exists for each domain value
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Explanation:
The inputs are x = -3, x = -1, x = 1, x = 5. They are the first coordinate listed of each point. We don't have any x values repeating so this means we have a function. Each input leads to exactly one output which is what choice B is stating. The domain is the set of allowed inputs, or x values. The range is the set of possible y outputs.
If we had something like (1,2) and (1,5) then the input x = 1 leads to more than one output (y = 2 and y = 5). This example means we don't have a function
If you graph the points (-3, -2), (-1,0), (1,0) and (5,-2) as shown in the attached image, then you'll notice that it is impossible to pass a single line through more than one point. Therefore this graph passes the vertical line test visually proving we have a function.
Going back to the example with (1,2) and (1,5), plotting these two points leads to the vertical line test failing implying we don't have a function.
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---------------------------------
Explanation:
The inputs are x = -3, x = -1, x = 1, x = 5. They are the first coordinate listed of each point. We don't have any x values repeating so this means we have a function. Each input leads to exactly one output which is what choice B is stating. The domain is the set of allowed inputs, or x values. The range is the set of possible y outputs.
If we had something like (1,2) and (1,5) then the input x = 1 leads to more than one output (y = 2 and y = 5). This example means we don't have a function
If you graph the points (-3, -2), (-1,0), (1,0) and (5,-2) as shown in the attached image, then you'll notice that it is impossible to pass a single line through more than one point. Therefore this graph passes the vertical line test visually proving we have a function.
Going back to the example with (1,2) and (1,5), plotting these two points leads to the vertical line test failing implying we don't have a function.
Answer:
x ≥ 661.424°F or x[661.424,∞) and x ≤ - 27°F or x(-∞,-27]
Step-by-step explanation:
The melting point of the substance is - 32.78°C, then the melting point in °F is given by
⇒
⇒
⇒ F = - 27.004°F
Again, the boiling point of the substance is 349.68°C, hence, the boiling point in °F is
⇒ F = 661.424°F
Therefore, the range of temperature in °F for which the substance will not be in liquid state will be x ≥ 661.424°F or x[661.424,∞) and x ≤ - 27.004°F or x(-∞,-27.004], where x is the temperature of the substance in °F. (Answer)