Answer: The predicted change in the boiling point of water is Δt = 0.0148 °C
Solution:
We will use the equation for boiling point elevation Δt
Δt = i Kb m
where the van't Hoff Factor i is equal to 3 since one molecule of barium chloride in aqueous solution will produce one Ba2+ ion and two Cl- ions. The molality m of the solution of 4.00 g of barium chloride dissolved in 2.00 kg of water can be calculated using the molar mass of barium chloride:
m = [4.00g BaCl2 * (1 mol BaCl2 / 208.233g BaCl2)] / 2.00kg H2O
= 0.009605 mol/kg
Therefore, the amount Δt the boiling point increases is
Δt = i Kb m
= (3) (0.512 °C·kg/mol) (0.009605 mol/kg)
= 0.0148 °C
We can also find the new boiling point T for the solution since we know that pure water boils at 100 °C:
Δt = T - 100°C T = Δt + 100°C = 0.0148 °C + 100°C = 100.0148°C
Answer:
Corn starch, one of the covalent compounds, is solid at room temperature. The property of being solid is more common to ionic compounds. So, the hypothesis was mostly supported except for this one data point.
Answer:
Sugar dissolves best in water
Carbon Dioxide dissolves best in water
(Not 100% sure on this one) Salt is the least soluble in water
I hope this helped :)
Answer:
There are 70 grams of KOH
Explanation:
First, we calculate the weight of 1 mol of KOH:
Weight 1 mol KOH: Weight K + Weight 0 + Weight H= 39g+ 1g+ 16g= 56 g/mol
1 mol-------56 g KOH
1,25 mol----x= (1,25 molx56 g KOH)/1 mol= <em>70 g KOH</em>