<u>Answer:</u> The pH of resulting solution is 9.08
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
........(1)
Molarity of HCl = 0.40 M
Volume of solution = 15.0 mL
Putting values in equation 1, we get:

Molarity of ammonia = 0.50 M
Volume of solution = 20.0 mL
Putting values in equation 1, we get:

The chemical reaction for hydrochloric acid and ammonia follows the equation:

Initial: 0.006 0.01
Final: - 0.004 0.006
Volume of solution = 15.0 + 20.0 = 35.0 mL = 0.035 L (Conversion factor: 1 L = 1000 mL)
- To calculate the pOH of basic buffer, we use the equation given by Henderson Hasselbalch:
![pOH=pK_b+\log(\frac{[salt]}{[base]})](https://tex.z-dn.net/?f=pOH%3DpK_b%2B%5Clog%28%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bbase%5D%7D%29)
![pOH=pK_b+\log(\frac{[NH_4Cl]}{[NH_3]})](https://tex.z-dn.net/?f=pOH%3DpK_b%2B%5Clog%28%5Cfrac%7B%5BNH_4Cl%5D%7D%7B%5BNH_3%5D%7D%29)
We are given:
= negative logarithm of base dissociation constant of ammonia = 
![[NH_4Cl]=\frac{0.006}{0.035}](https://tex.z-dn.net/?f=%5BNH_4Cl%5D%3D%5Cfrac%7B0.006%7D%7B0.035%7D)
![[NH_3]=\frac{0.004}{0.035}](https://tex.z-dn.net/?f=%5BNH_3%5D%3D%5Cfrac%7B0.004%7D%7B0.035%7D)
pOH = ?
Putting values in above equation, we get:

To calculate pH of the solution, we use the equation:

Hence, the pH of the solution is 9.08
Correct Question :
Mass of water = 50.003g
Temperature of water= 24.95C
Specific heat capacity for water = 4.184J/g C
Mass of metal = 63.546 g
Temperature of metal 99.95°C
Specific heat capacity for metal ?
Final temperature = 32.80°C
In an experiment to determine the specific heat of a metal student transferred a sample of the metal that was heated in boiling water into room temperature water in an insulated cup. The student recorded the temperature of the water after thermal equilibrium was reached. The data we shown in the table above. Based on the data, what is the calculated heat absorbed by the water reported with the appropriate number of significant figures?
Answer:
1642 J
Explanation:
Given:
Mass of water = 50.003g
Temperature of water= 24.95C
Specific heat capacity for water = 4.184J/g C
Mass of metal = 63.546 g
Temperature of metal 99.95°C
Specific heat capacity for metal ?
Final temperature = 32.80° C
To calculate the heat absorbed by water, Q, let's use the formula :
Q = ∆T * mass of water * specific heat
Where ∆T = 32.80°C - 24.95°C = 7.85°C
Therefore,
Q= 7.85 * 50.003 * 4.184
Q = 1642.32 J
≈ 1642 J
Answer:
See explanation
Explanation:
According to Avogadro's law, the volume of a given mass of gas is directly proportional to the number of molecules of gas present at constant temperature and pressure.
Hence; V1/n1 = V2/n2
The implication of this is, if there were X molecules present and the volume of the balloon is halved, the number of molecules of gas present is also halved. So, we now have X/2 number of gas molecules present in the balloon.
This is in accordance with the statement of Avogadro's law.
It is a value (of 1/2) that describes the angular momentum of an electron in either clockwise or in anti-clockwise direction..........
Multiply 9.0g/cm3 by 0.31g = 2.79cm3